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3 years ago

6

You need craft supplies. You buy bead for 12.75, ribbon for 4.50, felt for 0.99 and leather cord for 6.35. How much did you spen

d on craft supplies

1 answer:

Jobisdone [24]3 years ago

6 0

12.75+4.5+0.99+6.35= 12.75+4.5=17.25 .99+6.34=7.33 17.25+7.33= 24.58

$24.58

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Can someone plz solve this 6x + (9x + 4) - 11 = 21x - 7

qwelly [4]

Answer:

6x+9x+4-11=21x-7

15x-7=21x-7

15x-21x=0

x=0

8 0

2 years ago

Calculate volume of hemisphere with radius 3.2 cm

Olin [163]

Answer:

V ≈ 68.63 cm³

Step-by-step explanation:

the volume (V) of a sphere is calculated as

V = $\frac{4}{3}$ πr³

the volume of a hemisphere is half the volume of a sphere, so

V = $\frac{1}{2}$ × $\frac{4}{3}$ πr³ = $\frac{2}{3}$ πr³ , then

V = $\frac{2}{3}$ π × 3.2³

= $\frac{2}{3}$ π × 32.768

≈ 68.63 cm³ ( to 2 dec. places )

5 0

2 years ago

Find the approximate area of the triangle y x> O 30 square units O 15 square units 21 square units 45 square units

Fiesta28 [93]

Answer:

Step-by-step explanation:

a right triangle is half of a rectangle and the area of a rectangle is

area of rectangle = length × width

Area of a triangle is one half times the length times the width

area of triangle = 1/2 × length × width

in this case

length is the number of the y units

width is the number of x axis unit

area of triangle = 1/2 × length × width

area of triangle = 1/2 × (y units) × (x units) you need to count and insert

the number of units into the

equation

area of triangle = 1/2 × (??? y units ) × (??? x units ) do the math yourself

and see if you get one of

answers

6 0

3 years ago

Which expression is equivalent to 7a^3(6a^2+a^2)-4a^6?

Thepotemich [5.8K]

Simply simplify:

7a³(7a²)-4a^6 ⇒ 49a^6 - 4a^6 ⇒ 45a^6

Hope that helps!

3 0

3 years ago

For waht values of x do the vectors -1,0,-1), (2,1,2), (1,1, x) form a basis for R3?

DaniilM [7]

<h2>Answer:</h2>

The values of x for which the given vectors are basis for R³ is:

$x\neq 1$

<h2>Step-by-step explanation:</h2>

We know that for a set of vectors are linearly independent if the matrix formed by these set of vectors is non-singular i.e. the determinant of the matrix formed by these vectors is non-zero.

We are given three vectors as:

(-1,0,-1), (2,1,2), (1,1, x)

The matrix formed by these vectors is:

$\left[\begin{array}{ccc}-1&2&1\\0&1&1\\-1&2&x\end{array}\right]$

Now, the determinant of this matrix is:

$\begin{vmatrix}-1 &2 & 1\\ 0& 1 & 1\\ -1 & 2 & x\end{vmatrix}=-1(x-2)-2(1)+1\\\\\\\begin{vmatrix}-1 &2 & 1\\ 0& 1 & 1\\ -1 & 2 & x\end{vmatrix}=-x+2-2+1\\\\\\\begin{vmatrix}-1 &2 & 1\\ 0& 1 & 1\\ -1 & 2 & x\end{vmatrix}=-x+1$

Hence,

$-x+1\neq 0\\\\\\i.e.\\\\\\x\neq 1$

4 0

3 years ago