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3 years ago

Jannelle can drive an average of 295 miles on one tank of gas. How many miles can she drive on 16 tanks of gas?

Mathematics

1 answer:

Oksana_A [137]3 years ago

7 0

Jannelle could go 4,720 miles hope this helps

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According to his running log, Reid averaged 4 miles per week and 6 miles per week this month. By what percent has his average in

Bas_tet [7]

Answer:

24 cause u take 4 time 6 is 24 u got ya answer

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3 years ago

Sin40°-sin20°/cos220°-cos200=√3

Mumz [18]

Answer:

1.7320508

Step-by-step explanation:

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2 years ago

7 times a number is 3 thousand 5 hundered what is the number

babymother [125]

The number is 500. 500×7=3,500.

6 0

2 years ago

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Please help me!!!!!!!!

sergejj [24]

Answer:

Angle 1: 105

Angle 2: 75

Step-by-step explanation:

You know 2 is 75 because both lines are parallel.

To get 1 you subtract 75 from 180.

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2 years ago

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The estimated value of the integral from 0 to 2 of x cubed dx , using the trapezoidal rule with 4 trapezoids is

bulgar [2K]

The integral is approximated by the sum,

$\displaystyle\int_0^2f(x)\,\mathrm dx\approx\sum_{n=0}^4\frac12\times\frac{f(x_n)+f(x_{n+1})}2=\frac14\sum_{n=0}^3(f(x_n)+f(x_{n+1}))$

where $f(x)=x^3$ and $x_n=\dfrac12n$ , giving you

$\displaystyle\frac14\sum_{n=0}^3\bigg(\left(\frac n2\right)^3+\left(\frac{n+1}2\right)^3\bigg)$
$\displaystyle\frac1{32}\sum_{n=0}^3(n^3+(n+1)^3)$
$\displaystyle\frac1{32}\sum_{n=0}^3(2n^3+3n^2+3n+1)$

Faulhaber's formulas make short work of computing the sum. You have

$\displaystyle\sum_{n=0}^k1=k+1$
$\displaystyle\sum_{n=0}^kn=\frac{k(k+1)}2$
$\displaystyle\sum_{n=0}^kn^2=\frac{k(k+1)(2k+1)}6$
$\displaystyle\sum_{n=0}^kn^3=\frac{k^2(k+1)^2}4$

which gives

$\displaystyle\frac1{16}\sum_{n=0}^3n^3+\frac3{32}\sum_{n=0}^3n^2+\frac3{32}\sum_{n=0}^3n+\frac1{32}\sum_{n=0}^31$
$\displaystyle\frac{36}{16}+\frac{42}{32}+\frac{18}{32}+\frac4{32}$
$\implies\displaystyle\int_0^2x^3\,\mathrm dx\approx\frac{17}4=4.25$

4 0

3 years ago