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ludmilkaskok [199]
3 years ago
10

Start with 2 Rabbits.Each pair has 6 babies per month.How much will they have by the 12 month?

Mathematics
1 answer:
Nadya [2.5K]3 years ago
8 0
They will have 72 babies. This is because to make a pair, you need 2 rabbits. So all you have to do is multiply 12 by 6, and you’ll get 72
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Form the intersection for the following sets.
xxTIMURxx [149]

Answer:

  • {20}

Step-by-step explanation:

<u>Given sets</u>

  • R = {10, 15, 20}
  • S = {20, 25}

<u>Intersection of sets</u>

  • R ∩ S = {20}
4 0
4 years ago
Determine the value of a in the figure shown
galina1969 [7]

Answer:

d

Step-by-step explanation:

180-149= 31.

31+ 122= 153

180-153= 27

a= 27

3 0
3 years ago
3+3•3+3 <br> What does this equal<br> A)21<br> B)36<br> C)15
Svetllana [295]
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3 0
4 years ago
780 at 5.25 for 10 months what is the amount of simple interest
Annette [7]

Answer:

$814.13

Step-by-step explanation:

Recall that the simple interest formula is a=p(1+rt).

a= final amount (Unknown)

p=starting amount ($780)

r= interest rate (5.25= 0.0525%)

t=time in years (10 months =5/6 years)

Plug numbers into formula:

a=780(1+5.25*5/6)

Solve parenthesis first according to PEMDAS:

a=780(1.04375)

Multiply:

814.125

Round to nearest hundredth (cent):

$814.13

5 0
3 years ago
The number N = 100+100^2+100^3 + ... +100^n . Find the least possible value of n such that the number N is divisible by 11.
soldier1979 [14.2K]

It's a big alphabet, why confuse us with N and n?

Anyway, this one is a bit easier than it looks.  We're going to look at it mod 11, meaning we're only interested in the remainders when we divide by 11.  The nice thing about multiplication and addition is if we're going to take the remainder at the end, we can also take the remainders at the beginning and along the way and get the same answer, with smaller numbers.

That all sounds very complicated.  It's easier explained.

100 =9*11 +1 so has remainder 1 when divided by 11.  So if we multiply by 100 that's not going to change the remainder when we divided by 11; it's like multiplying by 1.

So 100, 100^2, 100^3, etc all have remainder 1 when divided by 11.  So we need to add up 11 of them to get a number that's divisible by 11.

Answer: 11


4 0
4 years ago
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