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Likurg_2 [28]
3 years ago
9

Exercise 10.4.1: Bayes' Theorem - detecting a biased coin. About (a) Sally has two coins. The first coin is a fair coin and the

second coin is biased. The biased coin comes up heads with probability .75 and tails with probability .25. She selects a coin at random and flips the coin ten times. The results of the coin flips are mutually independent. The result of the 10 flips is: T,T,H,T,H,T,T,T,H,T. What is the probability that she selected the biased coin
Mathematics
1 answer:
8_murik_8 [283]3 years ago
7 0

Answer:

0.026

Step-by-step explanation:

Given the result of 10 coin flips :

T,T,H,T,H,T,T,T,H,T

Number of Heads, H = 3

Number of tails, T = 7

Let :

B = biased coin

B' = non-biased coin

E = event

Probability that it is the biased coin:

P(E Given biased coin) / P(E Given biased coin) * P(E Given non-biased coin) * P(non-biased coin)

P(E|B)P(B) / (P(E|B)*P(B) + P(E|B')P(B')

([(0.75^3) * (0.25^7)] * 0.5) /([(0.75^3) * (0.25^7)] * 0.5) + (0.5^10) * 0.5

0.0000128746 / 0.00050115585

= 0.0263671875

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Sveta_85 [38]

Answer:

Wednesday is 45 to 18.

Thursday is 55 to 22

Step-by-step explanation:

Wednesday: The original ratio was 5 to 2 And the info tells us that the new ratio is ? to 18. To find the first part we have to find how we got from 2 to 18. 2 * 9 = 18. So to find out the first part you do 5 * 9 = 45. We multiply 5 because Thats the original 1st part. We multiply 9 because that's how we got to 18 in the 2nd part. So the answer is 45 for Wednesday.

Thursday: The original ratio was 5 to 2 And the info tells us that the new ratio is 55 to ?. To find the first part we have to find how we got from 5 to 55. 5 * 11 = 55. So to find out the 2nd part you do 2 * 11 = 55. We multiply 2 because That's the original 2nd part. We multiply 11 because that's how we got to 55 in the 1st part. So the answer is 22 for Thursday.

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A recent study found that 51 children who watched a commercial for Walker Crisps (potato chips) featuring a long-standing sports
hichkok12 [17]

Answer:

1

The claim is that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

2

The kind of test to use is a t -test because a t -test is used to check if there is a difference between means of a population

3

t  =  3.054

4

The p-value  is   p-value  =  P(Z >  3.054) = 0.0011291

5

The conclusion is  

There is sufficient evidence to conclude that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

The test statistics is  

Step-by-step explanation:

From the question we are told that

   The first sample size is  n_1  =  51

    The first sample  mean is \mu_1  =  36

    The second sample size is  n_2  =  41

    The second sample  size is  \mu_2  =  25

     The first standard deviation is  \sigma _1  =  21.4 \  g

    The second standard deviation is  \sigma _2  =  12.8 \  g

  The  level of significance is  \alpha =  0.05

The  null hypothesis is  H_o  :  \mu_1 = \mu_ 2

The  alternative hypothesis is  H_a :  \mu_1 > \mu_2

Generally the test statistics is mathematically represented as

    t  =  \frac{\= x_1 - \= x_2}{ \sqrt{ \frac{s_1^2}{n_1}  + \frac{s_2^2}{n_2}  } }

=>   t  =  \frac{ 36 - 25}{ \sqrt{ \frac{ 21.4^2}{51}  + \frac{ 12.8^2}{41}  } }

=> t  =  3.054

The  p-value is mathematically represented as

     p-value  =  P(Z >  3.054)

Generally from the z table  

             P(Z >  3.054) =  0.0011291

=>   p-value  =  P(Z >  3.054) = 0.0011291

From the values obtained  we see that p-value  < \alpha so  the null hypothesis is rejected

Thus the conclusion is  

  There is sufficient evidence to conclude that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

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