Answer:
8. $35.10
9. $59.63
10. $13.43
11. $70
12. Take the percent you pay (100-the discount) as a decimal and multiply it by the regular price.
Step-by-step explanation:
For finding the price we pay during a sale, we focus on the percent we pay. If 22% off is the sale, then we spend 78% or 100-22-78. We use this percent byb multiplying the price with a decimal. We convert percents into decimals by dividing the percent number by 100. For example, 78% divided by 100 becomes 0.78.
8. Percent off is 22%. We pay 78%=0.78.
45(0.78)=$35.10
9. Percent off is 33%. We pay 67%=0.67.
89(0.67)=$59.63
10. Percent off is 44%. We pay 56%=0.56.
23.99(0.56)=$13.43
11. Percent off is 75%. We pay 25%=0.25.
279.99(0.25)=$70
12. See explanation above.
Yo sup??
total distance travelled by Janae =sum of distance on the 2 semicircles+ sum of the distances on the 2 track
=2πr+2*l
l=3 miles
r=1 mile
So,
total distance=2*3.14*1+2*3
=6.28+6
=12.28
=12.3 miles
Therefore the correct answer is option D
Hope this helps
ANSWER: 427 miles
Okay so you have to divide 366 by 6 to see how many miles he drives each hour.
explanation:
366 / 6 = 61
He drove 61 miles each hour.
now they want to know how many miles he drove when he reached 7 hours.
so add 366 and another 61 miles for another hour.
366 + 61 = 427
He will travel 427 miles in 7 hours.
Ratio of complement of x : supplement of x
2 : 5
⇒ 2 times the supplement of x will be equal to 5 times the complement of x
5(90 - x) = 2 (180 - x)
450 - 5x = 360 - 2x
5x - 2x = 450 - 360
3x = 90
x = 30°
Complement of x = 90 - x = 90 - 30 = 60
Supplement of x = 180 - x = 180 - 30 = 150
Ratio:
60 : 150
60 ÷ 30 : 150 ÷ 30
2 : 5 (checked)
Answer:
Answer is B
Step-by-step explanation:
If point D with coordinates (a,b) is reflected over the line y=x then the image point D' coordinates are (b,a) (see picture for details).
The middlepoint M of segment DD' lhas coordinates and lies on the line y=x (since its coordinates are equal), DD' is perpendicular to the line y=x and DM=D'M. All these remarks show that the point D' is the image point of D.
