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BigorU [14]
4 years ago
10

Find the sale price of each item. Round to two decimal places when necessary.

Mathematics
1 answer:
Grace [21]4 years ago
3 0

Answer:

8. $35.10

9. $59.63

10. $13.43

11. $70

12. Take the percent you pay (100-the discount) as a decimal and multiply it by the regular price.

Step-by-step explanation:

For finding the price we pay during a sale, we focus on the percent we pay. If 22% off is the sale, then we spend 78% or 100-22-78. We use this percent byb  multiplying the price with a decimal. We convert percents into decimals by dividing the percent number by 100. For example, 78% divided by 100 becomes 0.78.

8. Percent off is 22%. We pay 78%=0.78.

45(0.78)=$35.10

9. Percent off is 33%. We pay 67%=0.67.

89(0.67)=$59.63

10. Percent off is 44%. We pay 56%=0.56.

23.99(0.56)=$13.43

11. Percent off is 75%. We pay 25%=0.25.

279.99(0.25)=$70

12. See explanation above.

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The eleventh term from the end of the AP 14, 19, 24, …………., 264 is
vazorg [7]

Answer:

<h2>The eleventh term of the sequence is 64</h2>

Step-by-step explanation:

The sequence given is an arithmetic sequence

14, 19, 24, …………., 264

The nth term of an arithmetic sequence is given as;

Tn = a+(n-1)d where;

a is the first term = 14

d is the common difference = 19-14=24-19 = 5

n is the number of terms = 11(since we are to look for the eleventh term of the sequence)

substituting the given values in the formula given;

T11 = 14+(11-1)*5

T11 = 14+10(5)

T11 = 14+50

T11 = 64

The eleventh term of the sequence is 64

6 0
4 years ago
a. Fill in the midpoint of each class in the column provided. b. Enter the midpoints in L1 and the frequencies in L2, and use 1-
Tresset [83]

Answer:

\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1}  & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7}  & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}

Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795

Step-by-step explanation:

Given

See attachment for class

Solving (a): Fill the midpoint of each class.

Midpoint (M) is calculated as:

M = \frac{1}{2}(Lower + Upper)

Where

Lower \to Lower class interval

Upper \to Upper class interval

So, we have:

Class 63-65:

M = \frac{1}{2}(63 + 65) = 64

Class 66 - 68:

M = \frac{1}{2}(66 + 68) = 67

When the computation is completed, the frequency distribution will be:

\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1}  & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7}  & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}

Solving (b): Mean and standard deviation using 1-VarStats

Using 1-VarStats, the solution is:

\bar x = 70.2903

\sigma = 3.5795

<em>See attachment for result of 1-VarStats</em>

8 0
3 years ago
What is 22% of 60? <br> 13.2<br> 27.3<br> 1,320<br> 38
Olenka [21]
13.2



Good luck! (((((:
7 0
4 years ago
Read 2 more answers
Sasha sells T-shirts. Each day she earns a set amount, plus a commission.
WARRIOR [948]

Answer:

Domain → 0 < x < 5

Step-by-step explanation:

Sasha sells T-shirts and earns a fixed amount plus a commission by selling each shirt. (As given in the table)

Table attached shows a linear function (A regular increase in total pay with the increase in number of shirts sold)

So the input values of the table (Number of shirts sold) will represent the domain of the linear function.

Hence, reasonable domain for the function will be → 0 < x < 5

5 0
3 years ago
How did these steps worked out ?​
Sergeeva-Olga [200]
The steps i took into doing these problems did very well for me
8 0
3 years ago
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