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Licemer1 [7]
3 years ago
10

Help any 1 please!?​

Mathematics
1 answer:
sveticcg [70]3 years ago
3 0

Yo sup??

total distance travelled by Janae =sum of distance on the 2 semicircles+ sum of the distances on the 2 track

=2πr+2*l

l=3 miles

r=1 mile

So,

total distance=2*3.14*1+2*3

=6.28+6

=12.28

=12.3 miles

Therefore the correct answer is option D

Hope this helps

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Is the relationship shown by the data linear? If so, model the data with an equation.
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Answer:

Therefore the equation of the line through ( -7 , 5 ) and ( -5 , 9) is

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Step-by-step explanation:

Given:

Let,

point A( x₁ , y₁) ≡ ( -7, 5 )  

point B( x₂ , y₂) ≡ (-5, 9)  

To Find:

Equation of Line AB =?

Solution:

Equation of a line passing through Two points A( x₁ , y₁) and B( x₂ , y₂)is given by the formula

(y - y_{1} )=(\frac{y_{2}-y_{1} }{x_{2}-x_{1} })\times(x-x_{1}) \\

Substituting the given values in a above equation we get

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Therefore the equation of the line through ( -7 , 5 ) and ( -5 , 9 ) is

Linear Relationship i.e y-5=2(x+7)

4 0
3 years ago
5x^2-41x+8=0 please helpp
jeka94

Answer:

Use the quadratic formula

=

−

±

2

−

4

√

2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}

x=2a−b±b2−4ac​​

Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.

5

2

−

4

1

+

8

=

0

5x^{2}-41x+8=0

5x2−41x+8=0

=

5

a={\color{#c92786}{5}}

a=5

=

−

4

1

b={\color{#e8710a}{-41}}

b=−41

=

8

c={\color{#129eaf}{8}}

c=8

=

−

(

−

4

1

)

±

(

−

4

1

)

2

−

4

⋅

5

⋅

8

√

2

⋅

5

2

Simplify

3

Separate the equations

4

Solve

Solution

=

8

=

1

5

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