8 gray buttons out of 20 buttons

Label each triangle

Ne4ueva [31]

Answer: Top right and left are ACUTE, Bottom right is RIGHT, and bottom left is OBTUSE.

4 0

3 years ago

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Please help this is due in tommorow! I will mark you as brainliest!

pshichka [43]

Answer:

325.26

Step-by-step explanation:

that's the answer because you have to multiply the top

I have question do we have to do something to the bottom?

5 0

3 years ago

If a = pi +3j - 7k, b = pi - pj +4k and the angle between a and is acute then the possible values for p are given by

PIT_PIT [208]

Answer:

The family of possible values for $p$ are:

$(-\infty, -4) \,\cup \,(7, +\infty)$

Step-by-step explanation:

By Linear Algebra, we can calculate the angle by definition of dot product:

$\cos \theta = \frac{\vec a\,\bullet\,\vec b}{\|\vec a\|\cdot \|\vec b\|}$ (1)

Where:

$\theta$ - Angle between vectors, in sexagesimal degrees.

$\|\vec a\|, \|\vec b \|$ - Norms of vectors $\vec {a}$ and $\vec{b}$

If $\theta$ is acute, then the cosine function is bounded between 0 a 1 and if we know that $\vec {a} = (p, 3, -7)$ and $\vec {b} = (p, -p, 4)$ , then the possible values for $p$ are:

Minimum ( $\cos \theta = 0$ )

$\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} > 0$

Maximum ( $\cos \theta = 1$ )

$\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} < 1$

With the help of a graphing tool we get the family of possible values for $p$ are:

$(-\infty, -4) \,\cup \,(7, +\infty)$

7 0

3 years ago

Simplify the following 3/4(1/2× - 12)+4/5

irga5000 [103]

Step-by-step explanation:

3/4 ×1/-24 +5/5

3×1/4×-24+4/5

3/-96+4/5

-3/96+4/5

-1/32+4/5

ans:123/160

3 0

4 years ago

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If Zach has 4 times as many dimes as quarters and they have a combined value of 455 cents, how many of each coins does he have?

aliya0001 [1]

<u>ANSWER: </u>

Zach has 28 dimes and 7 quarters.

<u>SOLUTION: </u>

Given, Zach has 4 times as many dimes as quarters

And they have a combined value of 455 cents,

We need to find how many of each coins does he have?

Let, the number of dimes be x and number of quarters be y.

Then, x = 4y → (1)

Total combined value = 455 cents

x(value of one dime) + y(value of one quarter) = 455 cents

x(10 cents) + x(25 cents) = 455 cents

10x + 25y = 455 → (2)

Now, substitute (1) in (2)

10(4y) + 25y = 455

40x + 25y = 455

65y = 455

y = 7

substitute y value in (1)

x = 4(7) = 28

Hence, zach has 28 dimes and 7 quarters.

4 0

3 years ago