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3 years ago

Three less than eight times the number is equal to half of 16 times the number after it was increased by one

Mathematics

1 answer:

finlep [7]3 years ago

6 0

Answer:

1) The question is aimed to determine the number that Laura is trying to come up with.

Such question is solved by stating an algebraic equation from the word statement, which is done step by step.

2) Using the name x for the unknown, the expression "three less than 8 times the number" is translated to: 8x - 3

3) The expression "half of 16 times the number after it was increased by 1" is translated to: (1/2) (16x + 1)

4) Finally, since they are equal, you can set the equation:

8x - 3 = (1/2) (16x + 1)

5) And solve for x in this way:

i) Distributive property:

8x - 3 = 8x + 1/2

ii) At this stage you can see that the both 8x terms (on the left and on the right) cancel each other, which leads to the impossibility to determine the value of the unknown:

-3 = 1/2 which is alwasy false, meaning that the equation has no solution.

Read more on Brainly.com - brainly.com/question/10888245#readmore

Step-by-step explanation:

hope it help

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CAN SOMEONE PLEASE HELP ME !!

Nataly_w [17]

With what number? With all? And why 5. It’s small for this difficult task.

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3 years ago

Students in a representative sample of 69 second-year students selected from a large university in England participated in a stu

Serhud [2]

Answer:

95% confidence interval estimate of μ, the mean procrastination scale for second-year students at this terval college is [39.34 , 42.66].

Step-by-step explanation:

We are given that for the 69 second-year students in the study at the university, the sample mean procrastination score was 41.00 and the sample standard deviation was 6.89.

Firstly, the pivotal quantity for 95% confidence interval for the true mean is given by;

P.Q. = $\frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean procrastination score = 41

s = sample standard deviation = 6.89

n = sample of students = 69

$\mu$ = population mean estimate

<em>Here for constructing 95% confidence interval we have used One-sample t test statistics because we don't know about population standard deviation.</em>

So, 95% confidence interval for the true mean, $\mu$ is ;

P(-1.9973 < $t_6_8$ < 1.9973) = 0.95 {As the critical value of t at 68 degree

of freedom are -1.9973 & 1.9973 with P = 2.5%}

P(-1.9973 < $\frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }$ < 1.9973) = 0.95

P( $-1.9973 \times{\frac{s}{\sqrt{n} } }$ < ${\bar X -\mu}$ < $1.9973 \times{\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-1.9973 \times{\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.9973 \times{\frac{s}{\sqrt{n} } }$ ) = 0.95

<u>95% confidence interval for </u> $\mu$ =[ $\bar X-1.9973 \times{\frac{s}{\sqrt{n} } }$ , $\bar X+1.9973 \times{\frac{s}{\sqrt{n} } }$ ]

= [ $41-1.9973 \times{\frac{6.89}{\sqrt{69} } }$ , $41+1.9973 \times{\frac{6.89}{\sqrt{69} } }$ ]

= [39.34 , 42.66]

Therefore, 95% confidence interval estimate of μ, the mean procrastination scale for second-year students at this terval college is [39.34 , 42.66].

5 0

3 years ago

Find the area of the polygon . All corners are 90 degrees .

natulia [17]

The composite figure is made up of 2 rectangles.

Area of the top rectangle = 9 x 10 = 90 m²

Area of the bottom rectangle = 30 x 9 = 270 m²

Area of the figure = 90 + 270 = 360m²

Answer: Area = 360m²

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4 years ago

Suppose the probability that a randomly selected man, aged 55-59, will die of cancer during the course of the year is startfra

Romashka-Z-Leto [24]

The probability that a randomly selected man dies of cancer during the course of the year = $\frac{300}{100000}= \frac{3}{1000}=0.003$

The probability that a randomly selected man does not die of cancer during the course of the year = $1-0.003=0.997$

The probability that atleast one man of this age dies of cancer is the complement of the probability that no man dies of cancer. In equation form we can write:

Probability that atleast one man of this age dies of cancer = 1 - No man at this age dies of cancer

The probability that no man dies of cancer out of 1000 selected men = $(0.997)^{1000}=0.04956$ , rounded of to 5 decimal places

Thus the probability that atleast one man at this age dies of cancer = 1 - 0.04956 = 0.95044

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3 years ago

What is a solution of the inequality shown below? 9 + b ≤ 2

Gala2k [10]

Answer:

$x\leq -7$

Step-by-step explanation:

i put into desmos graphing caculater

8 0

3 years ago

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