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stich3 [128]
3 years ago
15

The product of 33 and j

Mathematics
2 answers:
Alex787 [66]3 years ago
5 0
The "product" of two terms tells you that you're going to be multiplying them. When you multiply a number and a variable the number always goes first.

33j

This can also be written as 33 x j , 33 · j , (33)(j).
Kamila [148]3 years ago
4 0
33×j=33j
if j equal anything then just replace the number with the veritable.
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Step-by-step explanation:

The root has a multiplicity of 3, meaning that it crosses the x axis at x=2.

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2 years ago
The graph shows a journey in a car Help Fast!!!
Sever21 [200]

Answer: i think the answer would be c


i hope this helps you out!


Step-by-step explanation:


3 0
3 years ago
Help me please as soon as possible
SIZIF [17.4K]
If each case weighs 24 pounds, then 1p=24 pounds. so if we're trying to find a function of weight, p=24c.

Example: When you have 2 cases, you plug in a 2 for c

p=24c
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p=48

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6 0
3 years ago
Count the number of 5-digit numbers (in the decimal system; integers from 10000 to 99999) which are not divisible by 11.
Alexxandr [17]

Answer:

So total number which is not divisible by 11 = 89999-8181 = 81819  

Step-by-step explanation:

We have to find the total numbers which are not divisible by 11 from 10000 to 99999

Total number from 10000 to 99999 = 99999-10000+1=90000

Just after 10000 the number which is divisible by 11 is 10010

And just below 99999 the number which is divisible by 11 is 99990

Using AP formula

T_N=a+(n-1)d, here a is first term, d is common difference and n is number of terms

So 99990=10010+(n-1)11

n-1 = 8180

n= 8181

So total number which is not divisible by 11 = 90000-8181 = 81819

4 0
3 years ago
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devlian [24]
Add it tighter and it will make ur number then subtract that
4 0
3 years ago
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