Let H = Hailey, M = Megan, B = Bailey
H + M + B = 458
167 + M + B = 458
M + B = 291
152 ≤ M ≤ 164
If M = 152, B = 139
If M = 164, B = 127
Thus,
$127 ≤ B ≤ 139
Answer:
Because your sleep deprived and your head is clumped up with more equations. :( i wish school was easy
Step-by-step explanation:
Answer:
x - -5.78526086, -1.50769051, 2.29295138
Step-by-step explanation:
graph each side of the equation. the solution si the x-value of the point of intersection.
Answer:
...
against the wind, an airplane travels 3640 km in 7 hours.
with the wind, the same plane travels 6000 km in 6hrs.
...
let speed of plane in still air be x mph
speed of wind be y mph.
..
t=d/r
..
against wind speed = x-y mph
with wond speed = x=y mph
...
3640/(x-y)=7
3640 = 7x-7y
/7
520=x-y.....................1
...
6000/x+y = 6
6000 = 6x+6y
/6
1000=x+y.....................2
...
Add (1) & (2)
2x=1520
/2
x=760 mph speed of plane in still air
...
plug value of x in 2
1000=760+y
100-760=y
240 = y
240 mph speed of wind
Projectile motion is characterized by a motion that has two vector forces: the velocity along the x and y directions. As a result, the motion follows an arc-shaped direction. These two directions are actually independent of each other.
There are already derived equations for this so it is already convenient. However, your given equation for range is incomplete. The correct equation is:
R = v₀²sin2θ/g
where
R = 140 ft
v₀ = 120 ft/s
g = 32.2 m/s²
Substituting the values,
sin 2θ = Rg/v₀²
sin 2θ = (140)(32.2)/(120²)
sin 2θ = 0.313
2θ = sin ⁻¹ (0.313)
2θ = 18.24°
θ =18.24°/2
θ = 9.12°
