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Nuetrik [128]
2 years ago
5

Xin leans a 26-foot ladder against a wall so that it forms an angle of 78^{\circ} ∘ with the ground. What’s the horizontal dista

nce between the base of the ladder and the wall? Round your answer to the nearest hundredth of a foot if necessary
Mathematics
1 answer:
defon2 years ago
5 0

The ladder and the wall it leans on are illustrations of right triangle

The horizontal distance from the base of the ladder is 5.41 feet

<h3>How to determine the horizontal distance?</h3>

The given parameters are:

Length (L) = 26 feet

Angle of elevation (θ) = 78 degrees

The horizontal distance (D) is calculated using the following cosine ratio

cos(θ) = D/L

Substitute known values

cos(78) = D/26

Make D the subject

D = 26 * cos(78)

Multiply

D = 5.41

Hence, the horizontal distance from the base of the ladder is 5.41 feet

Read more about right triangles at:

brainly.com/question/2437195

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Answer:

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total amount = dn - 18n

Step-by-step explanation:

given data

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solution

we take original price paid for the game = d

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so that can we say

d -18

and

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3 years ago
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Answer:

33.08 m

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= 73 - 36

= 37

x = √37 = 6.08 m

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5 0
2 years ago
Solve for w p=1.2w/h^2
andreyandreev [35.5K]
Solve for w:
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(1.2 w)/h^2 = (6 w)/(5 h^2):
p = (6 w)/(5 h^2)
p = (6 w)/(5 h^2) is equivalent to (6 w)/(5 h^2) = p:
(6 w)/(5 h^2) = p
Multiply both sides by (5 h^2)/6:
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The right answer is A ! :)
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