Polygon Diagonals. The number of diagonals in a polygon = n(n-3)/2, where n is the number of polygon sides. For a convex n-sided polygon, there are n vertices, and from each vertex you can draw n-3 diagonals, so the total number of diagonals that can be drawn is n(n-3).
7 goes into 63 9 times so 6/7 you would take away one 9 so it would be 6 times 9 which is equal to 54
Answer: 54 students
Answer:
6/3
Step-by-step explanation:
The answer is 6/3 because if you go up 6 and the the right 3, you reach the point that hits the line.
Here are the ordered pairs
(4,3)
(8,6)
(-4,-3)
Hope this helped?
Answer:
Below
Step-by-step explanation:
First we can go ahead and create a general equation for this polynomial
Here are our roots :
x1 = - 3
x2 = -1
x3 = 1
Now because this function extends from quadrant 4 to 3, we know that this has been reflected in the x-axis :
f(x) = - ( x + 3 ) ( x + 1 ) ( x - 1 )
However if we look closely you can see that the graph appears to "bounce" off certain roots. In this case it bounces off x = 1. This means that this root is an order of 2. It also has a weird looking curve on x = - 3 which means that this root is an order of 3.
Our general equation will look like this :
f(x) = - ( x + 3 )^3 ( x - 1 )^2 ( x + 1 )
Now we need to sub in any point on the graph to solve for the <em>a </em>value. I'm just going to arbitrarily pick the y-intercept at ( 0 , -3 )
- 3 = - a ( 0 + 3 )^3 ( 0 - 1 )^2 ( 0 + 1 )
- 3 = - a (3)^3 (-1)^2 (1)
- 3 = - a (27)(1)(1)
- 3 = - a27
1/9 = a
Here is our FINAL equation :
f(x) = - 1/9 ( x + 3 )^3 ( x - 1 )^2 ( x + 1 )
Hope this helps! Best of luck <3
I would really appreciate a brainliest if possible :)
