Given:
The equation of a circle is
A tangent line l to the circle touches the circle at point P(12,5).
To find:
The gradient of the line l.
Solution:
Slope formula: If a line passes through two points, then the slope of the line is
Endpoints of the radius are O(0,0) and P(12,5). So, the slope of radius is
We know that, the radius of a circle is always perpendicular to the tangent at the point of tangency.
Product of slopes of two perpendicular lines is always -1.
Let the slope of tangent line l is m. Then, the product of slopes of line l and radius is -1.
Therefore, the gradient or slope of the tangent line l is 
.
The regular hexagon has both reflection symmetry and rotation symmetry.
Reflection symmetry is present when a figure has one or more lines of symmetry. A regular hexagon has 6 lines of symmetry. It has a 6-fold rotation axis.
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Rotation symmetry is present when a figure can be rotated (less than 360°) and still look the same as before it was rotated. The center of rotation is a point a figure is rotated around such that the rotation symmetry holds. A regular hexagon can be rotated 6 times at an angle of 60°
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Answer: 9^-16
Step-by-step explanation:
a^b*a^c= a^b+c
Answer:
Square each side
Subtract 1 from each side
Divide by 3
Step-by-step explanation:
sqrt(3x+1) = 4
Square each side
(sqrt(3x+1))^2 = 4^2
3x+1 = 16
Subtract 1 from each side
3x+1-1 = 16-1
3x= 15
Divide by 3
3x/3 = 15/3
x = 5
