X=width of a coccer pitch
2x-20=length of a soccer pitch
Area (rectangule)=length x width
We suggest this equation:
x(2x-20)=6000
2x²-20x=6000
2x²-20x-6000=0
x²-10x-3000=0
We solve this quadratic equation:
x=[10⁺₋√(100-4*1*-3000)]/2=[10⁺₋√(100+12000)]/2=
=(10⁺₋110)/2
we have two solutions:
x₁=(10-110)/2=-50, invalid solution.
x₂=(10+110)/2=60
x=60
2x-20=2(60)-20=120-20=100
Solution: the length is 100 m, and the width is 60 m.
To check:
Area=100 m*60 m=6000 m²
The twice of width is =2(60 m)=120 m,
20 m less than twice its width is: 120 m-20 m=100 m=the length.
1500m=1.5km so 1500 divided by 10= 150s it takes 150s to cover a distance of 1.5km
Answer:
-6.95 x 10^10
Step-by-step explanation:
Answer:
A and B
Step-by-step explanation:
3:4 multiplied by 2 is 6:8
3x2=6 4x2=8
3:4 multiplied by 3 is 9:12
3x3=9 4x3=12
