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andrezito [222]
3 years ago
9

en una granja quieren poner una cerca con forma octogonal para guardar las ocas por las noches.Ya han colocado dos de los lados

y han utilizado 8 metros de valla.Si sabemos que el apotema es 4,8 metros,¿cuql sera su perimetro?¿Y su area?
Mathematics
1 answer:
ratelena [41]3 years ago
3 0

Answer:

Perimeter = 32m

Area = 76.8m²

Step-by-step explanation:

Question:

On a farm they want to put an octagonal fence to keep the geese at night. They have already placed two of the sides and used 8 meters of fence. If we know that the apothem is 4.8 meters, what will be its perimeter? And your area?

Octagonal polygon is a polygon with 8sides.

Two sides of fence = 8m

One side of fence = 8/2 = 4m

Each sides = 4m

Apothem = 4.8m

Let's look at the steps that will enable us solve this question.

The area of a regular polygon is calculated as:

Area = ½ap

where a = the apothem of the polygon

p= the perimeter of the polygon.

Apothem is the distance between the centre of the polygon and the base of the polygon.

The perimeter (p) = The sum of all sides of the octagon

p = (4 + 4 + 4 + 4 + 4 + 4+ 4+ 4 )

p = 4(8)

perimeter (p) = 32m

Area = ½ ×a ×p = ½ × 4.8m × 32

Area = 153.6/2

Area = 76.8m²

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Ne4ueva [31]
The fraction would be 997/1000, since this decimal goes to the thousandths place.  
5 0
3 years ago
What is the area of a triangle that has a base of 10 ft and a height of 5 ft? A-15ft B-7.5ft C-25ft D-50ft​
weeeeeb [17]

Answer:

25

Step-by-step explanation:

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3 0
3 years ago
A system for tracking ships indicated that a ship lies on a hyperbolic path described by 5x2 - y2 = 20. the process is repeated
zysi [14]
Answer:
The ship is located at (3,5)

Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III

Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II

To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.

Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9

We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3

Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5

Based on the above, the position of the ship is (3,5).

Hope this helps :)
8 0
3 years ago
5=4b-12 hurry and make sure you put how you got the answer
PIT_PIT [208]

Answer:

4.25

Process:

  • 5=4b-12
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  • b=\frac{17}{4}
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5 0
3 years ago
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Answer:

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Step-by-step explanation:

3 0
3 years ago
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