Algebra 1 help please!

Determine the level of measurement of the variable. an officer's rank in the military Group of answer choices

ElenaW [278]

Answer:

Ordinal

Step-by-step explanation:

Level of measurement used in statistics summarizes what statistical analysis that is possible. There exist three types of level of measurement. The nominal, ordinal and Interval/Ratio level of measurement. Here, our primary focus will be the Ordinal level of measurement.

Ordinal level of measurement indicates the position in a sequence. In the military sector, the officer's rank is said to be Ordinal. This implies that the ordinal level of measurement categorizes variables according to hierarchy or ranks with a meaningful order. Still, the intervals and differences between the variables may not be equal.

3 0

3 years ago

How much water does it take to completely fill a pool that is 50m long, 25m wide, and 2 m deep?

viktelen [127]

Answer:

which is the volume of the water

it implies , volume=l*b*h

50m*25m*2m

2500m'3

6 0

4 years ago

Read 2 more answers

Litter such as leaves falls to the forest floor, where the action of insects and bacteria initiates the decay process. Let A be

Travka [436]

Answer:

D = L/k

Step-by-step explanation:

Since A represents the amount of litter present in grams per square meter as a function of time in years, the net rate of litter present is

dA/dt = in flow - out flow

Since litter falls at a constant rate of L grams per square meter per year, in flow = L

Since litter decays at a constant proportional rate of k per year, the total amount of litter decay per square meter per year is A × k = Ak = out flow

So,

dA/dt = in flow - out flow

dA/dt = L - Ak

Separating the variables, we have

dA/(L - Ak) = dt

Integrating, we have

∫-kdA/-k(L - Ak) = ∫dt

1/k∫-kdA/(L - Ak) = ∫dt

1/k㏑(L - Ak) = t + C

㏑(L - Ak) = kt + kC

㏑(L - Ak) = kt + C' (C' = kC)

taking exponents of both sides, we have

$L - Ak = e^{kt + C'} \\L - Ak = e^{kt}e^{C'}\\L - Ak = C"e^{kt} (C" = e^{C'} )\\Ak = L - C"e^{kt}\\A = \frac{L}{k} - \frac{C"}{k} e^{kt}$

When t = 0, A(0) = 0 (since the forest floor is initially clear)

$A = \frac{L}{k} - \frac{C"}{k} e^{kt}\\0 = \frac{L}{k} - \frac{C"}{k} e^{k0}\\0 = \frac{L}{k} - \frac{C"}{k} e^{0}\\\frac{L}{k} = \frac{C"}{k} \\C" = L$