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stiks02 [169]
2 years ago
13

F(x)=2x^2+3 and g(x)=x^2-7 find (f+g)(x)

Mathematics
1 answer:
defon2 years ago
3 0

Answer:

3x^2 -4

Step-by-step explanation:

F(x)=2x^2+3 and g(x)=x^2-7

(f+g)(x) =

We add the two functions together

(f+g)(x) =2x^2+3+x^2-7

I like to line them up vertically

(f+g)(x) =

2x^2 +3

+x^2  -7

------------------

3x^2 -4

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Ryan is remodeling his kitchen floor, which is 110 square feet. He used
irakobra [83]

Answer:

He will need 9 tiles

Step-by-step explanation:

Step one:

let us highlight the given parameters

Given data

the size of the kitchen floor is 110 ft^2

the size of the bathroom is 28 ft^2

he used 32.5 tiles for the kitchen

and used x tiles for the bathroom

Step two:

if he used 32 tiles for 110 ft^2 kitchen

he will use x tiles for 28 ft^2 bathroom

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3 years ago
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An icicle with a diameter of 15.5 centimeters at the top, tapers down in the shape of a cone with a length of
Helga [31]

Answer:

Step-by-step explanation:

Note: I will leave the answers as fraction and in terms of pi unless the question states rounding conditions to ensure maximum precision.

From the question, we can tell it is a inversed-cone (upside down)

Volume of Cone = \pi r^{2} \frac{h}{3}

a) Given Diameter , d = 15.5cm and Length , h = 350cm,

we first find the radius.

r = \frac{d}{2} \\=\frac{15.5}{2} \\=7.75cm

We will now find the volume of the cone.

Volume of cone  \pi (7.75)^{2} \frac{350}{3} \\= \frac{168175\pi }{24}

We know the density of ice is 0.93 grams per 1cm^{3}

1cm^{3} =0.93g\\\frac{168175\pi }{24}  cm^{3} =0.93(\frac{168175\pi }{24} )\\= 20473 g(Nearest Gram)

b) After 1 hour, we know that the new radius = 7.75cm - 0.35cm = 7.4cm

and the new length, h = 350cm - 15cm = 335cm

Now we will find the volume of this newly-shaped cone.

Volume of cone = \pi (7.4)^{2} \frac{335}{3} \\= \frac{91723\pi }{15} cm^{3}

Volume of cone being melted = New Volume - Original volume

= \frac{168175\pi }{24} -\frac{91723\pi }{15} \\= \frac{35697\pi }{40} cm^{3}

c) Lets take the bucket as a round cylinder.

Given radius of bucket, r = 12.5cm (Half of Diameter) and h , height = 30cm.

Volume of cylinder = \pi r^{2} h\\=\pi (12.5)^{2} (30)\\=\frac{9375\pi }{2} cm^{3}

To overflow the bucket, the volume of ice melted must be more than the bucket volume.

Volume of ice melted after 5 hours = 5(\frac{35697\pi }{40} )\\=\frac{35697\pi }{8} cm^{3}

See, from here of course you are unable to tell whether the bucket will overflow as all are in fractions, but fret not, we can just find the difference.

Volume of bucket - Volume of ice melted after 5 hours

= \frac{9375\pi }{2} -\frac{35697\pi }{8 } \\=\frac{1803\pi }{8}cm^{3}

from we can see the bucket can still hold more melted ice even after 5 hours therefore it will not overflow.

4 0
1 year ago
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