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3 years ago

PLEASE HELP QUICK 20 POINTS. Please as quick as possible I should have the answer in3 hours THANKS

Mathematics

1 answer:

Airida [17]3 years ago

6 0

Answer:

18 gallons

Step-by-step explanation:

the tank capacity is :

$71.98 ÷ $3.98 = 18 gallons

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Student Debt – Vermont: The average student loan debt of a U.S. college student at the end of 4 years of college is estimated to

mezya [45]

Answer:

The confidence interval is (24116.3878,24883.6122).

Step-by-step explanation:

We are given the following information in the question:

Population mean, $\mu$ = $23,500

Sample mean, $\bar{x}$ = $24,500

Sample standard deviation,s = $2,800

Sample size, n = 146

Confidence interval:

$\bar{x} \pm t_{critical}\frac{s}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at}~\alpha_{0.05} = \pm 1.655436$

$24500 \pm 1.65543(\frac{2800}{\sqrt{146}} ) = 24500 \pm 383.6122 = (24116.3878,24883.6122)$

The confidence interval is (24116.3878,24883.6122).

5 0

3 years ago

Anita invested $6000, some at 5% and the rest at 6%. If the yearly income is $337.50, what is the amount invested at each rate?

Pepsi [2]

Let the amount invested with 5% interest be x

Therefore, the amount invested with 6% interest will be (6000-x)

It is given that the total interest earned yearly is $337.5. Thus, the equation of interest will be:

$\frac{5}{100}x+\frac{6}{100}(6000-x)=337.5$

Multiplying both sides by 100 we get:

$5x+6(6000-x)=33750$

$5x+36000-6x=33750$

Subtracting both sides by 36000 we get:

$-x=-2250$

$\therefore x=2250$

Thus, the amount invested at 5% is $2250

Therefore, the amount invested at 6% will be $(6000-2250)=$3750

6 0

3 years ago

Johans age is given by the polynomial x^2-3x+7. Bret is younger and his age given by the polynomial x^2-x+1. What is the differe

yuradex [85]

(x^2-3x+7)-(x^2-x+1) = -2x+6

5 0

3 years ago

Write the expression for the Area of the polygon BORT MO 6 A= O A = 6m + mp O A = mp + 1/2(6m) O A = mp + 6p

anyanavicka [17]

We are asked to determine the area of the given figure. To do that we will divide the figure into a square and a triangle. The area of the square is the product of its dimension, therefore, the area is:

$A_{sq}=mp$

The area of the triangle is given by the following formula:

$A_t=\frac{bh}{2}$

Where "b" is the base and "h" is its height. Replacing the values:

$A_t=\frac{(6)(m)}{2}=\frac{1}{2}6m$

The total area is the sum of both areas:

$A=A_{sq}+A_t$

replacing the areas:

$A=mp+\frac{1}{2}6m$

7 0

1 year ago

The decreasing population, p, of owls in a national park is being monitored by ecologists and is modeled by the equation p=−0.

n200080 [17]

By solving a quadratic equation, it can be verified that

The owl population will disappear after 329.12 years

What is a quadratic equation?

At first it is important to know about equation

Equation shows the equality between two algebraic expressions by connecting the two algebraic expressions by an equal to sign.

A two degree equation is known as quadratic equation.

Here, a quadratic equation needs to be solved

The decreasing population, p, of owls in a national park is being monitored by ecologists and is modeled by the equation p= $-0. 4t^2+128t+1,200$

For population to disappear, p =0

$-0. 4t^2+128t+1,200 = 0\\0.4t^2 -128t - 1200 = 0\\4t^2 - 1280t - 12000 = 0\\4(t^2 - 320 t - 3000) = 0\\t^2 - 320t -3000 = 0\\t = \frac{-(-320)\pm \sqrt{(-320)^2 - 4 \times 1 \times (-3000)}}{2 \times 1}\\t = \frac{320 \pm 338.23}{2}\\t = \frac{320 + 338.23}{2} \ or \ t = \frac{320 - 338.23}{2}\\t = 329.115 \ or \ t = -9.115$

But t = -9.115 is not possible as time cannot be negative

So, the owl population will disappear after 329.12 years

To learn more about quadratic equation, refer to the link-

brainly.com/question/1214333

#SPJ4

7 0

1 year ago