Ask question

Ask question

All categories

3 years ago

6

An object that weighs 5 pounds on earth will weigh 2 pounds on mercury. The Statue of Liberty weighs 2,250 pounds. What would it

weigh on mercury?

2 answers:

murzikaleks [220]3 years ago

7 0

2/5=x/2250

2250x2=4500

4500/5=900 pounds

nexus9112 [7]3 years ago

6 0

2/5=x/2250
Cross multiply
2*2250=4500
5x=4500
Divide
4500/5=900
x=900 lbs

You might be interested in

17 1/4 over 100 as a decimal

Andrew [12]

Answer:

0.1725

Step-by-step explanation:

17 1/4 /100

17.25/100

0.1725

4 0

2 years ago

Read 2 more answers

Write a paragraph proof to prove that triangles BHD and FHC are congruent

Katena32 [7]

Answer:

Wdym is there any attachment ?

Step-by-step explanation:

4 0

3 years ago

The value of the varriable which satisfies the equation is called the _______ of the equation

scoray [572]

Answer:

solution

Step-by-step explanation:

solution is the answer

3 0

3 years ago

Two semicircles are attached to the sides of a rectangle as shown.

melomori [17]

Answer:

$157\ in^{2}$

Step-by-step explanation:

we know that

The area of the figure is equal to the area of rectangle plus the area of two semicircles

<u>The area of rectangle is equal to</u>

$A=14*5=70\ in^{2}$

<u>The area of the small semicircle is equal to</u>

$A=\pi r^{2} /2$

$r=5/2=2.5\ in$ -----> radius is half the diameter

substitute

$A=(3.14)(2.5^{2})/2=9.8125 in^{2}$

<u>The area of the larger semicircle is equal to</u>

$A=\pi r^{2} /2$

$r=14/2=7\ in$ -----> radius is half the diameter

substitute

$A=(3.14)(7^{2})/2=76.93\ in^{2}$

The area of the figure is equal to

$70+9.8125+76.93=156.7425=157\ in^{2}$

8 0

3 years ago

Read 2 more answers

If a recipe required 1 1/2 cups of sugar how many required to make M batches of cookies

Tema [17]

what does m mean first of a

5 0

3 years ago