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Tom [10]
3 years ago
12

CLUES

Mathematics
2 answers:
enot [183]3 years ago
6 0

Answer:

74

Step-by-step explanation:

a + b = 11

ab - ba = 27

10a + b - 10b - a = 27

10a - a + b - 10b = 27

9a - 9b = 27

9(a - b) = 27

a - b = 27 : 9

a - b = 3

a + b = 11

a - b = 3

_______ +

a + b + a - b = 11 + 3

2a = 14

a = 7

a + b = 11 => 7 + b = 11 => b = 11 - 7 => b = 4

ab = 74

storchak [24]3 years ago
3 0
The number is 74.
- It’s a two digit even number.
- 7 + 4 = 11
- 74 reversed is 47. 74 - 47 = 27.
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A circle with circumference 6 has an arc with a 20 central angle,<br> What is the length of the arc?
nirvana33 [79]

Answer:

0.3 units

Step-by-step explanation:

The ratio of the length of the arc to the circumference of the circle is proportional to the ratio of the central angle to the sum of angle in a circle.

\frac{l}{6}=\frac{20}{360}

This implies that:

l=\frac{20}{360}*6

This simplifies to: l=\frac{20}{60}

l=\frac{1}{3}=0.3 units

8 0
3 years ago
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Write an equation for the nth term of an arithmetic sequence then find a 25.
Damm [24]
Look up math way and type it in its free and it will help alot.
5 0
3 years ago
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The height distribution of NBA players follows a normal distribution with a mean of 79 inches and standard deviation of 3.5 inch
Shtirlitz [24]

Answer:

The probability will be "0.0111".

Step-by-step explanation:

The given values are:

Mean,

\mu = 79

Standard deviation,

\sigma = 3.5

Now,

⇒ \sigma\bar x = \frac{\sigma}{\sqrt n}

         =   \frac{3.5}{\sqrt 16}

         =0.875

⇒ P(\bar x > 81) = 1 - P(\bar x < 81)

So,

= 1 - P{\frac{(\bar x - \mu \bar x )}{ \sigma \bar x}  < \frac{(81 - 79) }{0.875} ]

= 1 - P(z < 2.2857)

= 0.0111

7 0
3 years ago
At noon, ship A is 130 km west of ship B. Ship A is sailing east at 25 km/h and ship B is sailing north at 20 km/h. How fast is
Hitman42 [59]

Answer:

answer = 12.87 km/h

Step-by-step explanation:

Given

Ship A is sailing east at 25 km/h = \frac{dx}{dt}

ship B is sailing north at 20 km/h =\frac{dy}{dt}

here x and y are the  sailing at t = 4 : 00 pm for ship A and B respectively

so we get x = 4 ×25 =100 km/h

                 y = 4× 20 = 80 km/h

let z is the distance between the ships, we need to find \frac{dz}{dt} at t = 4 hr

At noon, ship A is 130 km west of ship B (12:00 pm)

so equation will be

z^2 = (130-x)^2 + y^2......................(i)\\put x = 100 and y = 80 \\\\we |  | get \\

z^2 = 30^2 + 80^2\\z =\sqrt{7300} km/h

derivative first equation w . r. to t we get

2z\frac{dz}{dt} =-2(130-x)\frac{dx}{dt}+2y\frac{dy}{dt}

\frac{dz}{dt} =\frac{1}{z}[(x -130)\frac{dx}{dt} +y\frac{dy}{dt}]

\frac{dz}{dt} = \frac{( -20\times25 + 80\times20)}{\sqrt{7300} }

     = \frac{1100}{85.44}\\  = 12.87km/h

8 0
2 years ago
write the equation of a line in slope intercept form that is perpendicular to the line y = 3/5 x - 1 and passes through the poin
Simora [160]
Can you write complete question
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