Pete took a sample of moviegoers to see how many are seeing a comedy. Sample size: 175 Number seeing a comedy: 42 Population: 1,
1 answer:
Answer: Part A : c = n.p
Part B = 366 moviegoers
Step-by-step explanation: In part A, to predict the number of moviegoers, we have to find the <u>proportion</u> of the sample that does the activity, which will called <u>p</u>. Since <u>p</u> is a percentage, to determine how many moviegoers are seeing a comedy, you multiply it by the sample size, <u>n</u>.
Therefore: c = n.p
For part B, based on the the sample:
p = = 0.24
The total population is given: 1,525
c = 0.24.1,525
c = 366
Based on the sample, <u>366</u> <u>people</u> are seeing a comedy.
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The completely factored form of the provided polynomial is (p -2) (p+ 2) (p² +4). The option 4 is the correct option.
<h3>What is polynomial?</h3>Polynomial equations is the expression in which the highest power of the unknown variable is n (n is a real number).
The polynomial equation given in the problem is,
Let the factor form of the polynomial is f(p). Thus,
Using the formula of difference of squares, we get,
Thus, the completely factored form of the provided polynomial is (p -2) (p+ 2) (p² +4). The option 4 is the correct option.
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Answer:
(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.
(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.
(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.
Step-by-step explanation:
Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.
If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:
- np ≥ 10
- n(1 - p) ≥ 10
The three populations has the following proportions:
p₁ = 0.10
p₂ = 0.30
p₃ = 0.50
(1)
Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:
Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.
(2)
Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:
Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.
(3)
Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:
Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.