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Akimi4 [234]
3 years ago
15

The function ƒ(x) = is translated 3 units in the positive y-direction and reflected across the y-axis. Select the correct equati

on for the resulting function.
Multiple choice answers in attachment image

Mathematics
2 answers:
lidiya [134]3 years ago
7 0

Answer:

A) ƒ(x) =  + 3

Step-by-step explanation:

A. f(x)=−x+3

Explanation:

It is stated that the function f(x) is translated 3 units in the positive y-direction. This means that the function f(x) is moved 3 units upwards.

In transforming functions, a upwards vertical translation (moving the function upwards) of a units is done by: f(x) + a.

This means that in order to move f(x) 3 units upwards, we need to add 3 to the given function. This now makes our function:

f(x)=x+3

Finally, it is also stated that it is reflected across the y-axis. For reflection across the y-axis, the transformation can be done by simply multiplying -1 to x only

f(x)=−1×x+3

f(x)=−x+3

Therefore, the answer is A

Ivan3 years ago
5 0

Answer:

I think it's D but I'm not sure

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Answer:

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The equation d=0.05v2+1.1v models the distance, d, that it takes are car traveling v miles per hour to come to a complete stop.
liq [111]

Answer:

  • <u>Hannah was not speeding because her speed was about 61 mph, which is below the speed limit.</u>

Explanation:

Just to correct some typos, this is the complete question:

<em />

<em>The equation d=0.05v² +  1.1v models the distance, d, that it takes a car traveling at a speed of v miles per hour to come to a complete stop. If Hannah’s car stopped after travelling 250 feet on a highway with a speed limit of 65 mph, was Hannah speeding? Explain using math whether she was speeding and how you know.</em>

<em />

<h2>Solution</h2>

<em />

To find whether Hannah was speeding, you must find the velocity that is solution for the equation:

  • 250=0.05v² +  1.1v

<em />

Write it in standard form:

  • 0.05v² +  1.1v - 250 = 0

Use the quadratic formula:

       v=\dfrac{-1.1\pm\sqrt{(1.1)^2-4(0.05)(-250)}}{2(0.05)}

      v=\dfrac{-1.1\pm 7.1561}{0.1}

       v=60.6\text{ or }v=-82.6

The speed can only be positive; thus, it is about 61 miles per hour, which is below the speed limit of 65mph.

In conclusion, she was not speeding.

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