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Bumek [7]
3 years ago
15

Find the smallest integer k such that 60k is aperfect square​

Mathematics
1 answer:
Travka [436]3 years ago
5 0

Answer:  k = 15

<u>Step-by-step explanation:</u>

60 times some number k must be a perfect square.

Factor 60 to see which values do not have a pair:

60 = 2 · 2 · 3 · 5   --> 60 =<u> 2 · 2</u> · 3 · 5

                                                        ↓

                                                     3 · 5   are not pairs

So,  you need to multiply 60 by 15 to make a perfect square

60 × 15 = 900      →          \sqrt{900}=30

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Suppose the distance between x and zero is 6. write an inequality
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0 < /6/ (absolute value) 

That is your inequality since the subject is about the distance away from zero then using common sense you would make the 6 get put in between the 2 absolute value lines ( not trying to be rude, if the explanation seems rude to you im sorry)
4 0
3 years ago
What is the simplified form of the following expression? 2√27+√12-3√3-2√12
LiRa [457]

Answer:

√3

Step-by-step explanation:

The given expression to be simplified is

2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12}

but

2 \sqrt{27}=2\sqrt{9 \times 3}=2 \times \sqrt{9}\times \sqrt{3}=2 \times 3 \times\sqrt{3}=6 \sqrt{3}

\sqrt{12}=\sqrt{4\times3}= \sqrt{4}\times \sqrt{3}=2\sqrt{3}

Since √12=2√3,this implies that,

2\sqrt{12}=2\times2\sqrt{3}=4 \sqrt{3}

Therefore,

2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12}=6\sqrt{3}+2\sqrt{3}-3 \sqrt{3} -4\sqrt{3}

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=\sqrt{3}

The simplified form of ,

2 \sqrt{27}+\sqrt{12}-3\sqrt{3}-2 \sqrt{12} is √3

8 0
3 years ago
what is the equation in point-slope form of the line that passes through the point (3.-2)and has a slope of 2/3?​
Nookie1986 [14]
Dudu que tu es un homme de moi et je suis kiikii8k
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3 years ago
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Step-by-step explanation:

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8 0
4 years ago
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ira [324]

Answer:

3.75

Step-by-step explanation:

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Hope I helped! If so, may I get Brianliest and a Thanks?

Thank you, have a good one! =)

5 0
3 years ago
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