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frozen [14]
3 years ago
13

Suppose ABC is a right triangle with sides​ a, b, and c and right angle at C. Find the unknown side length using the Pythagorean

theorem and then find the values of the six trigonometric functions for angle B.

Mathematics
1 answer:
Leno4ka [110]3 years ago
3 0

Answer:

a = \sqrt{7}

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.:

<em>Suppose ABC is a right triangle with sides​ a, b, and c and right angle at C. Find the unknown side length using the Pythagorean theorem and then find the values of the six trigonometric functions for angle B. when b=3 and c=4</em>.

My answer:

We will Pythagoras theorem, which states that the sum of squares of two legs of a right triangle is equal to the square of the hypotenuse of right triangle. Because the question says that ABC is a right triangle.

a^2+b^2=c^2

Given that: b=3 and c=4

a^2+3^2=4^2a^2+9=16a^2+9-9=16-9a^2=7

so a = \sqrt{7}

We know that tangent relates opposite side of a right triangle with adjacent side.

\text{tan}(B)=\frac{a}{b}\\\text{tan}(B)=\frac{\sqrt{7}}{3}

Please have a look at the attached photos.

You might be interested in
What is the answer to 9÷2/3
Karo-lina-s [1.5K]

Answer:

27/2

Step-by-step explanation:

9 : 2/3 =

9 * 3/2 =

(3*9=27)

27/2 Is your answer



6 0
2 years ago
Read 2 more answers
Find y when x=14 if y varies directly with x2 and y=72 when x=6
ICE Princess25 [194]
This should help you:


8 0
3 years ago
the polynomial ky^3+3y^2-3 and 2y^3-5y+k when divided by (y-5) leave the same remainder in each case. Find the value of k.
marshall27 [118]

Answer:

k=\frac{153}{124}

Step-by-step explanation:

According to the Remainder Theorem; when P(y) is divided by y-a, the remainder is p(a).

The first polynomial is :

p(y)=ky^3+3y^2-3

When p(y) is divided by y-5, the remainder is

p(5)=k(5)^3+3(5)^2-3

p(5)=125k+75-3

p(5)=125k+72

When the second polynomial:

m(y)= 2y^3-5y+k is divided by y-5.

The remainder is;

m(5)= 2(5)^3-5(5)+k

m(5)= 225+k

The two remainders are equal;

\implies 125k+72=225+k

\implies 125k-k=225-72

\implies 124k=153

k=\frac{153}{124}

3 0
3 years ago
NEED HELP FAST PLEASE !!!!Which of the following is an equation of the translation y = cos x, shifted π units to the right?
Verdich [7]

Answer:

2 one

Step-by-step explanation:

6 0
2 years ago
Find a equation of a line that is perpendicular to y=-4x+3 and passes through the point (4,-1).
Marina86 [1]

Given:

The given equation is:

y=-4x+3

A line is perpendicular to the given line and passes through the point (4,-1).

To find:

The equation of required line.

Solution:

The slope intercept form of a line is:

y=mx+b

Where, m is slope and b is y-intercept.

We have,

y=-4x+3

Here, the slope of the line is -4 and the y-intercept is 3.

Let the slope of required line be m.

We know that the product of slopes of two perpendicular lines is -1. So,

m\times (-4)=-1

m=\dfrac{-1}{-4}

m=\dfrac{1}{4}

The slope of required line is m=\dfrac{1}{4} and it passes through the point (4,-1). So, the equation of the line is:

y-(-1)=\dfrac{1}{4}(x-4)

y+1=\dfrac{1}{4}(x)-\dfrac{4}{4}

y=\dfrac{1}{4}x-1-1

y=\dfrac{1}{4}x-2

Therefore, the equation of the required line is y=\dfrac{1}{4}x-2.

5 0
2 years ago
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