Answer:
Functions of an operating system. An operating system provides three essential capabilities: It offers a UI through a CLI or GUI; it launches and manages the application execution; and it identifies and exposes system hardware resources to those applications -- typically, through a standardized API.
Explanation:
Answer:
In a series connection, the current is the same through each component regardless of any kind of components are used or their values. The voltage drops across each component in the circuit are dependent upon the values of the components used in the circuit. Another way to view a series connection is that the positive end of each component is connected to the negative end of the previous component in a 'one after the other' arrangement. The negative end of each component is also connected to the positive end of the next component.
It is one of which every component is arranged in a series connection. Hence series circuit will have same current at all points of the circuit. The voltage drop across each component in the circuit adds up to sum of voltage source across each component and of an equivalent component value. Breaking of the series circuit will make entire circuit to stop working. Suppose consider the three bulbs are connected in series connection and if even one bulb burns out or broken then all the three bulbs will stop working as well. In series circuit components like current (I) is sum of all the element and Voltage is sum of all the voltage drops and resistance is the sum of individual resistances.
Explanation:
Get a dedicated server with 6-10gb RAM, which might be able to run a lot, while staying up with no lag.
Answer:
C. Modern Programming Language Skills
Explanation:
Answer:
Code to the answer is shown in the explanation section
Explanation:
import java.util.Scanner;
public class Question {
public static void main(String args[]) {
Scanner scan = new Scanner(System.in);
System.out.println("Please enter the days of the month: ");
int daysOfMonth = scan.nextInt();
int minuteOfMonth = daysOfMonth * 60 * 24;
System.out.println(minuteOfMonth);
}
}
// 60 represents the number of minutes in one hour
// 24 represents the number of hours in a day
