Hello,
6b) (i) As you can see, in the first year the price drops from 27,000 to 17,000. (Look at year 0-1 on the x axis). To find the percentage drop, find the difference between the two values and divide it over the initial value of 27,000.
So, the percentage drop in the first year is:
(27000-17000) / (27000) = 0.37, or a 37% drop
The answer is 37%.
(ii) For this question, we basically have the same process as the previous question except for the second year.
From year 1 to year 2, the value starts at 17,000 and ends at 15,000.
To find the percentage drop, we do:
(17000 - 15000) / (17000) = 0.118 ≈ 0.12, or a 12% drop
The answer is 12%.
6c) To find the percentage depreciation over the first 5 years, we look at the initial value (x = 0) and the value after 5 years (x = 5), and use these values in the same percentage formula we have been using.
The initial value of the car is 27,000, and after 5 years the value is 8,000.
This is a percentage drop of (27000 - 8000) / (27000) = 0.70, or a 70% drop.
The answer is 70%.
Hope this helps!
The 3 consecutive numbers are 88, 89, and 90. So 90 is the answer.
Answer:
0.02
Step-by-step explanation:
Given a normal distribution :
Mean income (m) = 25000
Standard deviation of income (s) = 6000
X ≥ 12000
Using the relation to fund the standardized score :
Zscore =(x - m) / s
Zscore = ( 12000 - 25000) / 6000
Zscore = -13000 / 6000
Zscore = - 2.167
Using a z probability calculator :
P(Z ≤ - 2.167) = 0.015117
= 0.02
6 is equal to 42/7, and 3 and 5/7 is 26/7 so 42-26 = 16/7 which is also 2 and 2/7 ths
The answer to the question is 378bd
