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velikii [3]
4 years ago
5

An 88 N forces pushes an object 15 m. how much work did the force do on the object

Physics
1 answer:
Natasha2012 [34]4 years ago
6 0
Work = force x distance
So 88x15 = work
1,320N/m = work
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Where are protons, neutrons, and electrons in the atom?
PilotLPTM [1.2K]

Answer:

The protons and the neutron are located in the nucleus and the electrons is the outermost region

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3 years ago
A 1200 kg car accelerates from 13 m/s to 17 m/s. find the change in momentum of the car.
mixas84 [53]
P=4800kgm/s
As
p=mΔv
where p is momentum, m is mass and v is velocity
Given values is
m =1200kg
Δv= 17m/s-13m/s=4m/s
Now
p=mΔv
p=(1200kg)*(4m/s)
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3 years ago
A student releases a ball from rest on an inclined plane and measures that it travels a distance of 0.6 m in a time of 4.0 s. Fi
Korvikt [17]

The average speed of the ball is 0.15 m/s.

The average speed of the ball can be calculated using the formula below.

<h3 /><h3> Average speed: </h3>

This is the ratio of the total distance to the total time traveled by a body

<h3 /><h3>Formula:</h3>
  • S = d/t.................. Equation 1

<h3>Where:</h3>
  • S = Average speed
  • d = total distance
  • t = total time.

From the question,

<h3>Given:</h3>
  • d = 0.6 m
  • t = 4.0 s

Substitute these values into equation 1

  • S = 0.6/4
  • S = 0.15 m/s

Hence, the average speed of the ball is 0.15 m/s.

Learn more about average speed here: brainly.com/question/4931057

8 0
3 years ago
In your experiment, you measure a total deflection of 4.12 cm when an electric field of 1.10×103V/m is established between the p
Bond [772]

Answer:

B_0 = 1.69 \times 10^{-4}\ T

Explanation:

given,

total deflection = 4.12 cm

Electric field = 1.1 ×10³ V/m

plate length = 6 cm

distance between them = 12 cm

using formula

v_0 = \sqrt{\dfrac{q\epsilon_0d}{ym}(\dfrac{d}{2}+L)}

q = 1.6 × 10⁻¹⁹ C

m = 9.11 x 10⁻³¹ kg

d = 0.06 m

L = 0.12 m

v_0 = \sqrt{\dfrac{1.6 \times 10^{-19}\times 1.1 \times 10^{3}\times 0.06}{0.0412\times 9.11 \times 10^{-31} }(\dfrac{0.06}{2}+0.12)}

v_0 = 6496355.63 m/s

v_0 = \dfrac{E}{B_0}

B_0 = \dfrac{E}{v_0}

B_0 = \dfrac{1.1\times 10^{3}}{6496355.63}

B_0 = 1.69 \times 10^{-4}\ T

5 0
3 years ago
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