Answer:
Hey
it would be 20 m
If you walk away 30 m then come back 10 you are now 20 m away from your starting point.
Answer:
0.001152m
Explanation:
Linear expansivity of a material is the change in length of the material per unit length per degree rise in temperature. Mathematically,
¢ = ∆L/L1∆°C
¢ is the linear expansivity of the material = 12 x 10⁻⁶ °C⁻¹
Where ∆L is the change in length = L2-L1
L2 is the final length = ?
L1 is the initial length = 12m
∆°C is the change in temperature = °C2 - °C1 = 50-(-30) = 80°C
Substituting this values inside the formula to get the final length L2 after expansion, we have;
12 x 10⁻⁶ °C⁻¹ = L2-12/12×80
12 x 10⁻⁶ °C⁻¹ = L2-12/960
L2-12= 960×12 x 10⁻⁶ °C⁻¹
L2-12 = 0.001152
L2 = 12+0.001152
L2 = 12.001152m
Expansion will be the change in length L2-L1 = 12.001152-12
= 0.001152m
The expansion cracks between the slabs should be 0.001152m wide to prevent buckling
Answer:
Explanation:
From the 1st Law of linear motion which states that when a body goes into motion, it will continue doing so until it is stopped by force. So the body of the rider keeps moving until it is been stopped and the stopping could be as a result of an impact of any part of the body which includes the head it an object. Also the 3rd Law of Motion will also be applicable because for every action, there will be equal and opposite reaction. The magnitude of the impact will be as a result of the force with which the crash took place as well.
When crashes take place the rider does not always experience a head impact square on with a solid obstruction. During a bike crash, your head comes in contact with the ground. The ground exerts a force that causes your head to stop moving. Often impact will be at an angle and may not be head first. It may be your shoulder will hit first, then your side, and then your head will receive a glancing blow against the ground as you slide.
The ground exerts so much force that it can stop our forward motion within seconds. Without your motorcycle helmet, your head experiences a huge amount of concentrated force during a crash.
Answer:
P=627.47W
Explanation:
To solve this problem we have to take into account, that the work done by the winch is
![W=Fh](https://tex.z-dn.net/?f=W%3DFh)
the force, at least must equal the gravitational force
![F=Mg=(156kg)(9.8\frac{m}{s^2})=1258.8N](https://tex.z-dn.net/?f=F%3DMg%3D%28156kg%29%289.8%5Cfrac%7Bm%7D%7Bs%5E2%7D%29%3D1258.8N)
with force the tension in the cable makes the winch go up.
The work done is
![W=(1258.8N)(58.0m)=73010.4J](https://tex.z-dn.net/?f=W%3D%281258.8N%29%2858.0m%29%3D73010.4J)
To calculate the power we need to know what is the time t. But first we have to compute the acceleration
The acceleration will be
![v_f^2=v_0+2ah\\a=\frac{v_f^2}{2h}=\frac{(24.9\frac{m}{s})}{2(58.0m)}=0.214\frac{m}{s^2}](https://tex.z-dn.net/?f=v_f%5E2%3Dv_0%2B2ah%5C%5Ca%3D%5Cfrac%7Bv_f%5E2%7D%7B2h%7D%3D%5Cfrac%7B%2824.9%5Cfrac%7Bm%7D%7Bs%7D%29%7D%7B2%2858.0m%29%7D%3D0.214%5Cfrac%7Bm%7D%7Bs%5E2%7D)
and the time t
![v_f=v_0+at\\t=\frac{v_f}{a}=116.35s](https://tex.z-dn.net/?f=v_f%3Dv_0%2Bat%5C%5Ct%3D%5Cfrac%7Bv_f%7D%7Ba%7D%3D116.35s)
The power will be
![P=\frac{W}{t}=\frac{73010.4J}{116.35s}=627.47W](https://tex.z-dn.net/?f=P%3D%5Cfrac%7BW%7D%7Bt%7D%3D%5Cfrac%7B73010.4J%7D%7B116.35s%7D%3D627.47W)
HOPE THIS HELPS!!
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