The trickiest part of this problem was making sure where the Yakima Valley is.
OK so it's generally around the city of the same name in Washington State.
Just for a place to work with, I picked the Yakima Valley Junior College, at the
corner of W Nob Hill Blvd and S16th Ave in Yakima. The latitude in the middle
of that intersection is 46.585° North. <u>That's</u> the number we need.
Here's how I would do it:
-- The altitude of the due-south point on the celestial equator is always
(90° - latitude), no matter what the date or time of day.
-- The highest above the celestial equator that the ecliptic ever gets
is about 23.5°.
-- The mean inclination of the moon's orbit to the ecliptic is 5.14°, so
that's the highest above the ecliptic that the moon can ever appear
in the sky.
This sets the limit of the highest in the sky that the moon can ever appear.
90° - 46.585° + 23.5° + 5.14° = 72.1° above the horizon .
That doesn't happen regularly. It would depend on everything coming
together at the same time ... the moon happens to be at the point in its
orbit that's 5.14° above ==> (the point on the ecliptic that's 23.5° above
the celestial equator).
Depending on the time of year, that can be any time of the day or night.
The most striking combination is at midnight, within a day or two of the
Winter solstice, when the moon happens to be full.
In general, the Full Moon closest to the Winter solstice is going to be
the moon highest in the sky. Then it's going to be somewhere near
67° above the horizon at midnight.
What is the definition of newton
The speed of the car passing you is 6 m/s while car is moving 6 m/s behind the car.
<h3>Relative velocity of the car</h3>
The speed of the car passing you is determined by applying relative velocity principle as shown below;
Vr = Va - Vb
Vr = 26 m/s - 32 m/s
Vr = -6 m/s
Thus, the speed of the car passing you is 6 m/s while car is moving 6 m/s behind the car.
Learn more about relative velocity here: brainly.com/question/17228388
#SPJ1
Answer:
E = 3456 J
Explanation:
The electrical energy expended in a resistor can be easily calculated by using the following formula:
where,
E = Energy Expended = ?
I = current through 5 ohm resistor = 2.4 A
R = Resistance = 5 ohms
P = Electrical Power = VI
Since,
V = IR (Ohm's Law)
Therefore,
P = (IR)(I) = I²R = (2.4 A)²(5 ohms) = 28.8 Watt
t = time taken = (2 min)(60 s/1 min) = 120 s
Therefore,
E = (28.8 Watt)(120 s)
<u>E = 3456 J</u>
It is a chemical change. I always think of a chemical/physical change as if you could reverse it back as it started off, for example if you stepped on a can you can reverse the can back probably not exactly like it was before but you can still reverse it so this would be a physical change, and if you baked a pizza you could not reverse the dough and everything else back.
