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4 years ago

12

Which phrase best describes wave motion? movement of energy through space or a medium movement of matter through space movement

of energy within a particle movement of air molecules through a medium

1 answer:

melomori [17]4 years ago

4 0

<span>movement of energy through space or a medium Hope this works! ;3</span>

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A ball is thrown horizontally from a 16 m -high building with a speed of 2.0 m/s .

BigorU [14]

Answer:

3.61 m

Explanation:

First, find how long it takes to land.

Given (in the y direction):

Δy = 16 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

(16 m) = (0 m/s) t + ½ (9.8 m/s²) t²

t = 1.81 s

Given (in the x direction):

v₀ = 2.0 m/s

a = 0 m/s²

t = 1.81 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (2.0 m/s) (1.81 s) + ½ (0 m/s²) (1.81 s)²

Δx = 3.61 m

4 0

3 years ago

Two wires of the same material and having the same volume, are fixed

Setler79 [48]

Answer:

48 kg

Explanation:

Given that the two wires are of same material, so their value of young's modulus will be same

Assuming that the wires are cylindrical in shape

As radius of the first wire is half that of the second wire and therefore the area of cross-section of the first wire will be one-fourth of the second wire( ∵ wire is cylindrical, the cross-sectional part will be circle and the area of the circle = π × r² )

As the volume is same for both wires

∴ π × ( $r_{1}$ )² × $l_{1}$ = π × ( $r_{2}$ )² × $l_{2}$

Here

$r_{1}$ is the radius of the first wire

$r_{2}$ is the radius of the second wire

$l_{1}$ is the length of the first wire

$l_{2}$ is the length of the second wire

⇒ π × (( $r_{2}$ )² ÷ 4) × $l_{1}$ = π × ( $r_{2}$ )² × $l_{2}$ (∵ radius of first wire is half that of the second wire)

By cancelling the same terms on both sides

we get

$l_{1}$ = 4 × $l_{2}$

⇒ Length of first wire will be four times of the length of second wire

<h3>Strain is defined as the elongation per unit length</h3>

Strain in first wire = ΔL ÷ $l_{1}$ = ΔL ÷ (4 × $l_{2}$ )

where ΔL is the elongation of the wire which in this case is same in both wires

Strain in second wire = ΔL ÷ $l_{2}$

∴ Strain in second wire is four times of strain in first wire

<h3>Stress = F ÷ A</h3>

where F is the force perpendicular to the cross-sectional area

A is the area of cross-section

Force in first wire = $m_{1}$ × g

where $m_{1}$ is the mass hanged to the first wire

g is the acceleration due to gravity

Force in second wire = $m_{2}$ × g

where $m_{2}$ is the mass hanged to the second wire

g is the acceleration due to gravity

Let $A_{1}$ be the cross-sectional area of first wire

$A_{2}$ be the cross-sectional area of second wire

$A_{2}$ = 4 × $A_{1}$ (∵ cross=sectional area of the wire = π × (radius of the wire)² )

Stress in first wire = ( $m_{1}$ × g) ÷ ( $A_{1}$ )

Stress in second wire = ( $m_{2}$ × g) ÷ ( $A_{2}$ ) = ( $m_{2}$ × g) ÷ (4 × $A_{1}$ )

<h3>Young's modulus is defined as Stress per unit strain</h3>

As Young's modulus is same for both wires, Stress per unit strain must be same for both wires

Stress per unit strain of first wire = (( $m_{1}$ × g) ÷ ( $A_{1}$ )) ÷ (ΔL ÷ (4 × $l_{2}$ ))

Stress per unit strain of second wire = (( $m_{2}$ × g) ÷ (4 × $A_{1}$ )) ÷ (ΔL ÷ $l_{2}$ )

By equating them we get

$m_{2}$ = 16 × $m_{1}$

⇒ $m_{2}$ = 16 × 3 = 48 kg

∴ $m_{2}$ = 48 kg

5 0

3 years ago

Capacitor 2 has half the capacitance and twice the potential difference as capacitor 1.What is the ratio Uc1/Uc2.

Colt1911 [192]

Answer:

1/2

Explanation:

The energy stored in a capacitor is given by:

$U=\frac{1}{2}CV^2$

where

C is the capacitance

V is the potential difference

For capacitor 1, we have

$U_1=\frac{1}{2}C_1V_1^2$

Capacitor 2 has

$C_2 = \frac{C_1}{2}$ (half the capacitance of capacitor 1)

$V_2 = 2 V_1$ (twice the potential difference of capacitor 1)

So the energy of capacitor 2 is

$U_2=\frac{1}{2}C_2V_2^2=\frac{1}{2}(\frac{C_1}{2})(2V_1)^2=C_1 V_1^2$

So, the ratio between the two energies is

$\frac{U_1}{U_2}=\frac{\frac{1}{2}C_1 V_1^2}{C_1 V_1^2}=\frac{1}{2}$

3 0

3 years ago

Light with a wavelength of 600 nm is incident on a gemstone made of cubic zirconia (ᡦ =2.18) from air. The light makes an angle

gregori [183]

Answer:

500 THz .

Explanation:

Velocity of light in air = 3 x10⁸ m /s

wave length of light = 600 nm

= 600 x 10⁻⁹ m

= 6 x 10⁻⁷ m

frequency in air = velocity in air / wave length in air

= 3 x 10⁸ / 6 x 10⁻⁷

= .5 x 10¹⁵ Hz

= 5 x 10¹⁴Hz

= 500 x 10¹² Hz

= 500 THz

When light enters the medium of gem , its wavelength and velocity changes in such a way that its frequency remains constant. So in the medium of gem also its frequency remains 500 THz .

3 0

3 years ago

Distinguish between endangered and extinct species.

Julli [10]

Answer and Explanation:

The distinction between Endangered species and Extict species is Given as under:

Endangered Species:

Endangered species are categorized as those species of flora and fauna which are on the verge of extinction if not provided timely protection in order to save them from getting extinct.

Some of the endangered species are African Penguin, Bengal Tiger, Blue Whale, etc

Extinct Species:

Those species of Flora and Fauna which have vanished completely or either from the wild i.e., that individuals of that species are not alive any more and have completely disappear from the earth.

In practice, if a species is not seen for over a period of 50 years it is considered to be extinct.

Some of the extinct species are Dodo, Passenger Pigeon, Great Aulk, etc.

7 0

3 years ago