Answer:
Electric force, 
Explanation:
Given that,
Electric charge 1, 
Electric charge 2, 
Distance, 
To find,
The electric force between these two sets of charges.
Solution,
There exists a force between two electric charges and this force is called electrostatic force. It is equal to the product of electric charged divided by square of distance between them.

k is the electrostatic constant


So, the electric force between these two sets of charges is
.
Answer:
d = 1.954 Km
Explanation:
given,
total distance, D = 2.5 Km
in stretch A to B =
speed = 99 Km/h = 99 x 0.278 = 27.22 m/s time =t
in stretch B to C
time = 3.4 s
In stretch C to D
speed = 48 Km/h = 48 x 0.278 = 13.34 m/s time =t
we know,
distance = speed x time
distance of BC
using equation of motion
v = u + a t
27.22 = 13.34 - a x 3.4
a = 4.08 m/s²
uniform deceleration is equal to 4.08 m/s²
distance traveled in BC


s = 68.94 m

3000 = 27.5 t + 68.94 + 13.33 t
40.83 t = 2931.06
t = 71.79 s
distance travel in AB
distance = s x t
d = 27.22 x 71.79
d = 1954 m
d = 1.954 Km
distance between A and B is equal to 1.954 Km.
Answer:
2, 8 and shell
Explanation:
Neon as atomic number 10. Since for each shell, electrons equal 2n².
When n = 1, 2n² = 2(1)² = 2
When n = 2, 2n² = 2(2)² = 8
So it fills both the first and second shell with 2 and 8 electrons respectively to achieve its stable atomic state. The rest of the 8 electrons go into the second shell because the first shell has achieved its stable dual configuration of two electrons. The next shell requires a maximum of 8 electrons to achieve stability so, the remaining electrons fill it up to achieve the stable octet configuration.
Speed = (distance covered) / (time to cover the distance).
= (1.92 meters) / (4.47 x 10⁻⁸ second)
= 42,950,000 meters/second (rounded to the nearest 10,000 m/s)
That's about 96.1 million miles per hour, or about 14% of the speed of light.
Answer:5.21 N
Explanation:
Given
B=5.210 T
I=2 A
L=0.5 m
Given Wire is perpendicular to Magnetic field




F=5.210 N
as 1 Tesla =1 N/A/m