A ball is thrown into the air with an upward velocity of 36 ft/s. Its height h in feet after t seconds is given by the function
h = –16t2+ 36t + 9. In how many seconds does the ball reach its maximum height? Round to the nearest hundredth if necessary.
What is the ball’s maximum height?
The ball reaches a height of 29.25 ft after 1.125 seconds
Step-by-step explanation:
The maximum height of a parabola can always be found by looking for the vertex. You can find the x value (or in this case the t value) of a vertex by using -b/2a in which a is the coefficient of x^2 and b is the coefficient of x.
-b/2a
-(36)/2(-16)
-36/-32
1.125 seconds
Now to find the height, we input that value in for t
