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3 years ago

(50 points) A diameter of a circle has endpoints P(-10, -2) and Q(4,6)

Mathematics

1 answer:

Gala2k [10]3 years ago

8 0

Answer:

Step-by-step explanation:

The center of the circle is the midpoint of the two end points of the diameter.

Formula

Center = (x2 + x1)/2 , (y2 + y1)/2

Givens

x2 = 4

x1 = - 10

y2 = 6

y1 = - 2

Solution

Center = (4 - 10)/2, (6 - 2)/2

Center = -6/2 , 4/2

Center = - 3 , 2

So far what you have is

(x+3)^2 + (y - 2)^2 = r^2

Now you have to find the radius.

You can use either of the endpoints to find the radius.

find the distance from (4,6) to (-3,2)

r^2 = ( (x2 - x1)^2 + (y2 - y1)^2 )

x2 = 4

x1 = -3

y2 = 6

y1 = 2

r^2 = ( (4 - -3)^2 + (6 - 2)^2 )

r^2 = ( (7)^2 + 4^2)

r^2 = ( 49 + 16)

r^2 = 65

Ultimate formula is

(x+3)^2 + (y - 2)^2 = 65

The radius is √65 = 8.06

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2 years ago

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Answer:

$y=\frac{4}{5}e^{t}-\frac{4}{5}e^{-\frac{2}{5}t}$

Step-by-step explanation:

The given equation 5y'' + 3y' - 2y =0 can be written as

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Solving for complementary function we have Roots of $(5D^{2}+3D-2)$ as follows

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Thus the complementary function becomes

y= $y=c_{1}e^{m_{1}t}+c_{2}e^{m_{2}t}$

where

$m_{1},m_{2}$ are calculated roots

thus solution becomes

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Now to solve for the coefficients we use the given boundary conditions

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hence the solution becomes

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3 years ago

Question 2

alina1380 [7]

6/6 is not correct 88/88 jeo

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3 years ago

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