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Leto [7]
3 years ago
7

A charity organization had a fundraiser where each ticket was sold for a fixed price $70. They had to sell a few tickets just to

cover necessary production costs. After selling 10 tickets, they were still at a net loss of $800(due to the production costs). Let p represent the net profit (in dollars)when they have sold n tickets
Mathematics
1 answer:
lina2011 [118]3 years ago
4 0

Answer:

  p = 70n -1500

Step-by-step explanation:

The slope-intercept form of the equation is ...

  p = 70n +b

We know that p = -800 for n = 10, so we can find b:

  -800 = 70·10 +b

  -800 -700 = b = -1500

The net profit equation is ...

  p = 70n -1500

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a dental company has rolls of floss that are 1872 in long they want to put the distance in the yard on their label what is the d
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Nine yards of ribbon are cut into 8 equal pieces what is the length of each piece of ribbon. Write a division expression to repr
PSYCHO15rus [73]

Answer:

x=\frac{9}{8}\ yards

x=1.125\ yards

Step-by-step explanation:

Let's call x the length of each piece in yards

If the ribbon is cut into 8 equal pieces then the sum of the pieces is:

x+x+x+x+x+x+x+x=8x

Then:

8x=9\ yards

Now we solve the equation for x

8x=9\ yards

Divide both sides of equality by 8

\frac{8}{8}x=\frac{9}{8}\ yards

x=\frac{9}{8}\ yards

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3 years ago
Why might working with n a commission basis make dealing with finances more difficult?
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Answer: The commission is paid according to sales amounts that are likely to vary from month to month.

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8 0
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Place the three functions in order from the fastest decreasing average rate of change to the slowest decreasing average rate of
victus00 [196]

Answer:

g(x), f(x) and h(x)

Step-by-step explanation:

Given

Interval: (0,3)

See attachment for functions f(x), g(x) and h(x)

Required

Order from fastest to slowest decreasing average rate of change

The average rate of change is calculated as:

Rate = \frac{f(b) - f(a)}{b - a}

In this case:

(a,b) = (0,3)

i.e.

a = 0\\b=3

For f(x)

f(x) = 16(\frac{1}{2})^x

Rate = \frac{f(b) - f(a)}{b - a}

Rate = \frac{f(3) - f(0)}{3 - 0}

Rate = \frac{f(3) - f(0)}{3}

Calculate f(3) and f(0)

f(x) = 16(\frac{1}{2})^x

f(3) = 16(\frac{1}{2})^3 = 16 * \frac{1}{8} = 2

f(0) = 16(\frac{1}{2})^0 = 16 * 1 = 16

So:

Rate = \frac{f(3) - f(0)}{3}

Rate = \frac{2 - 16}{3}

Rate = -\frac{14}{3}

For g(x)

Rate = \frac{g(b) - g(a)}{b - a}

Rate = \frac{g(3) - g(0)}{3 - 0}

Rate = \frac{g(3) - g(0)}{3}

From the table of g(x)

g(3) = 1

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So:

Rate = \frac{1 - 27}{3}

Rate = -\frac{26}{3}

For h(x)

Rate = \frac{h(b) - h(a)}{b - a}

Rate = \frac{h(3) - h(0)}{3 - 0}

Rate = \frac{h(3) - h(0)}{3}

From the graph of h(x)

h(3) = -3

h(0) = 4

So:

Rate = \frac{-3 - 4}{3}

Rate = -\frac{7}{3}

So, the calculated rates of change are:

f(x) = -\frac{14}{3} = -4.67

g(x) = -\frac{26}{3} =-8.67

h(x) = -\frac{7}{3} =-2.33

By comparison:

From the fastest decreasing to slowest, the order is: <em>g(x), f(x) and h(x)</em>

4 0
3 years ago
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