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3 years ago

Write an equation that represents a vertical stretch by a factor of 3 and a reflection in the x-axis of the graph of g(x)=|x|.

Mathematics

1 answer:

Dmitry [639]3 years ago

3 0

Answer:

(x,y) ---> (3x,3y) 3 units reflected on the x-axis

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Solve completely (all missing sides and all missing angles) using trig ratios or laws. Round to the nearest tenth.

hodyreva [135]

Answer:

Step-by-step explanation:

3. Use Cosine law to find the length of the unknown side (PR)

q² = p² + r² - 2prCos Q

q is the opposite side of ∠Q;

p is the opposite side of ∠P; p = 33

r is the opposite sides of ∠R ; r = 67

q² = 33² + 67² - 2* 33*67 Cos 19°

= 1089 + 4489 - 4422 * 0.95

= 1089 + 4489 - 4200.9

= 1377.1

q = √1377.1

q = 37.1

PR = 37.1

To find the angle use law of sin

$\sf \dfrac{q}{Sin \ Q} =\dfrac{p}{Sin \ P}\\\\\\\dfrac{37.1}{Sin \ 19}=\dfrac{33}{Sin \ P} \\\\\\\dfrac{37.1}{0.33}=\dfrac{33}{Sin \ P}\\\\\\37.1* Sin \ P = 33 *0.33\\\\Sin \ P =\dfrac{33*0.33}{37.1}$

Sin P = 0.3

$P = Sin^{-1} 0.3\\$

P = 17.5°

∠R = 180 - (19 + 17.5)

= 143.5°

6 0

2 years ago

The sum of two numbers is 59 and the difference is 5 what are the numbers

svlad2 [7]

Answer:

32 and 27

Step-by-step explanation:

59 - 5 = 54

54 ÷ 2 = 27( smallest no. )

27 + 5 = 32( largest no. )

3 0

3 years ago

Read 2 more answers

Volume of triangular prism

lukranit [14]

Answer: 225m^3

Step-by-step explanation:

Volume = Bh where "B" is the area of the base and "h" is the height

So, area of the base = 1/2(length)(height) = 1/2(5)(9) = 22.5 m^2.

Then multiply by the height.

22.5x10= 225m^3

3 0

3 years ago

Use the given numbers.

Scilla [17]

Answer:

on the third number it says 344,636 and there is a double 4

5 0

3 years ago

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The end points of one diagonal of a rhombus are (-5,2) and (1,6). If the coordinates of the 3rd vertexare (-6,10), what are the

ad-work [718]

Look at the picture.

$E\left(\dfrac{-5+1}{2};\ \dfrac{2+6}{2}\right)\to E\left(\dfrac{-4}{2};\ \dfrac{8}{2}\right)\to E(-2;\ 4)$

$\vec{BE}=[-2-(-6);\ 4-10]=[4;\ -6]$

$D(x;\ y)\\\\\vec{ED}=[x-(-2);\ y-4]=[x+2;\ y-4]\\\\\vec{ED}=\vec{BE}\ therefore\\\\ \ [x+2;\ y-4]=[4;\ -6]\to x+2=4\ and\ y-4=-6\\\\x=2\ and\ y=-2\\\\Answer:\ \boxed{A.\ (2;\ -2)}$

8 0

3 years ago