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Marina CMI [18]
2 years ago
8

PLEASE HELP ASAPPP !!! WILL GIVE BRAINLIEST AND 5 STAR RATING

Mathematics
1 answer:
natta225 [31]2 years ago
4 0

Answer:

1/3

Step-by-step explanation:

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The difference of the squares of two positive consecutive even integers is 84. Find the integers.
ziro4ka [17]

Answer:

The two integers are 20 and 22.

Step-by-step explanation:

Let x be the first integer.

(x+2)^{2}-x^{2} = 84\\x^{2} +4x+4-x^{2} = 84\\4x = 80\\x = 20

3 0
3 years ago
Ninety-one percent of products come off the line within product specifications. Your quality control department selects 15 produ
Allisa [31]

Answer:

Probability of stopping the machine when X < 9 is 0.0002

Probability of stopping the machine when X < 10 is 0.0013

Probability of stopping the machine when X < 11 is 0.0082

Probability of stopping the machine when X < 12 is 0.0399

Step-by-step explanation:

There is a random binomial variable X that represents the number of units come off the line within product specifications in a review of n Bernoulli-type trials with probability of success 0.91. Therefore, the model is {15 \choose x} (0.91) ^ {x} (0.09) ^ {(15-x)}. So:

P (X < 9) = 1 - P (X \geq 9) = 1 - [{15 \choose 9} (0.91)^{9}(0.09)^{6}+...+{ 15 \choose 15}(0.91)^{15}(0.09)^{0}] = 0.0002

P (X < 10) = 1 - P (X \geq 10) = 1 - [{15 \choose 10}(0.91)^{10}(0.09)^{5}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0013

P (X < 11) = 1 - P (X \geq 11) = 1 - [{15 \choose 11}(0.91)^{11}(0.09)^{4}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0082

P (X < 12) = 1- P (X \geq 12) = 1 - [{15 \choose 12}(0.91)^{12}(0.09)^{3}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0399

Probability of stopping the machine when X < 9 is 0.0002

Probability of stopping the machine when X < 10 is 0.0013

Probability of stopping the machine when X < 11 is 0.0082

Probability of stopping the machine when X < 12 is 0.0399

8 0
3 years ago
How many different license plates can be produced using 4 digits and 2 letters if the first digit cannot be the number 0 and the
Rainbow [258]
650 letter permutations * 5040 numbers permutations = total licence number possible = 3,276,000
3 0
3 years ago
HELP NEEDED ASAP! WOULD BE APPRECIATED
Kamila [148]

First, write an inequality equation:

0.25x + 0.1y = 2

There's your first answer. You got this!

6 0
3 years ago
Change to standard form. Can someone help with these 3 please, ty!
grigory [225]

Answer:x + 12y = 4

9x + y = 10

-9x + y = -7

Step-by-step explanation:idk for sure tho man

3 0
3 years ago
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