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Fiesta28 [93]
4 years ago
13

what are the minimume, first quartile, median, third quartile, and maximum of the data set? 2 6 12 8 3 9 14 20

Mathematics
2 answers:
Gre4nikov [31]4 years ago
4 0
To get the indicated values we re-arrange the set of numbers in ascending order:
<span>2 6 12 8 3 9 14 20
rearranging gives us:
2,3,6,8,9,12,14,20
Minimum-2
First quartile-5.25
Median-8.5
Third quartile-12.50
Maximum-20

</span>
Blababa [14]4 years ago
4 0

Answer:

Given data set is : 2 6 12 8 3 9 14 20

We shall re-arrange the set of numbers in ascending order to get a clear concept:

2 3 6 8 9 12 14 20

1. Minimum: The minimum is the least value of the data set that is 2.

First quartile: The first quartile value is the median for the numbers before the median. 2 3 6 8 the value is \frac{2+3+6+8}{4}= 4.75

Median: The average of the center two numbers. \frac{8+9}{2}=8.5

Third quartile: The third quartile is the same as first but take last 4 values, 9 12 14 20 the value is \frac{9+12+14+20}{4}= 13.75

Maximum: The highest value number in the data set which is 20.

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The vertex form of the given equation, y = -6x² + 3x + 2, is expressed as: y = -6(x - 0.25)² + 2.375.

<h3>What is an Equation in Vertex Form?</h3>

The vertex form of an equation is expressed as, y = a(x - h)² + k, where:

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Given the equation, y = -6x² + 3x + 2, factor the equation:

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Rewriting the equation as perfect squares, we would have:

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The vertex form of y = -6x² + 3x + 2 is, y = -6(x - 0.25)² + 2.375.

Learn more about vertex form of an equation on:

brainly.com/question/13912185

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