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Fiesta28 [93]
3 years ago
13

what are the minimume, first quartile, median, third quartile, and maximum of the data set? 2 6 12 8 3 9 14 20

Mathematics
2 answers:
Gre4nikov [31]3 years ago
4 0
To get the indicated values we re-arrange the set of numbers in ascending order:
<span>2 6 12 8 3 9 14 20
rearranging gives us:
2,3,6,8,9,12,14,20
Minimum-2
First quartile-5.25
Median-8.5
Third quartile-12.50
Maximum-20

</span>
Blababa [14]3 years ago
4 0

Answer:

Given data set is : 2 6 12 8 3 9 14 20

We shall re-arrange the set of numbers in ascending order to get a clear concept:

2 3 6 8 9 12 14 20

1. Minimum: The minimum is the least value of the data set that is 2.

First quartile: The first quartile value is the median for the numbers before the median. 2 3 6 8 the value is \frac{2+3+6+8}{4}= 4.75

Median: The average of the center two numbers. \frac{8+9}{2}=8.5

Third quartile: The third quartile is the same as first but take last 4 values, 9 12 14 20 the value is \frac{9+12+14+20}{4}= 13.75

Maximum: The highest value number in the data set which is 20.

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3 0
3 years ago
En un triángulo rectángulo A es un ángulo agudo y Sen A = 4/5 ¿Cuál será el valor de Tan A?
Nonamiya [84]

Answer:

\displaystyle \tan A=\frac{4}{3}

Step-by-step explanation:

<u>Funciones Trigonométricas</u>

La identidad principal en trigonometría es:

sen^2A+cos^2A=1

Si sabemos que A es un ángulo agudo (que mide menos de 90°), su seno y coseno son positivos.

Dado que Sen A = 4/5, calculamos el coseno:

cos^2A=1-sen^2A

Sustituyendo:

\displaystyle cos^2A=1-\left(\frac{4}{5}\right)^2

\displaystyle cos^2A=1-\frac{16}{25}

\displaystyle cos^2A=\frac{25-16}{25}

\displaystyle cos^2A=\frac{9}{25}

Tomando raíz cuadrada:

\displaystyle cos\ A=\sqrt{\frac{9}{25}}=\frac{3}{5}

La tangente se define como:

\displaystyle \tan A=\frac{sen\ A}{cos\ A}

Substituyendo:

\displaystyle \tan A=\frac{\frac{4}{5}}{\frac{3}{5}}

\displaystyle \tan A=\frac{4}{3}

6 0
3 years ago
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