Jill rides her horse 5 miles due north and 3 miles due east. What is magnitude and direction of her ride
1 answer:
First magnitude...
d^2=5^2+3^2
d^2=25+9
d^2=34
d=√34
now for direction...
tanα=y/x
α=arctan(y/x) and we know y=5 and x=3 so
α=arctan(5/3)
α≈59.03624
So the vector of her ride is:
√34, 59.03624° or if you prefer...
√34, 59°2'10" (in standard angle position)
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