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Flura [38]
4 years ago
5

Make this sentence into an equation 4 times the number which is v less that 2 is 11

Mathematics
2 answers:
Cerrena [4.2K]4 years ago
7 0

Since the number we are multiplying by 4 is v less than 2 therefore we have (v-2) and since it asked to multiply by 4 we have 4(v-2)=11 and then it said it is equal to 11 therefore we have:

4(v-2)=11

zvonat [6]4 years ago
3 0

4xV-2=11

(4 multiplied by the variable V subtracted by 2 equals 11).


Hope this helps, bud! :P

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Answer:

B and F

Step-by-step explanation:

The simple golden rule that we need to know here is

<em><u>"The probability of any event is always between 0 and 1 inclusive"</u></em>

<em><u /></em>

If an event has a probability of p(x), we can say:

0 \leq p(x) \leq 1

Also, probability is ALWAYS POSITIVE.

Thus,

A) OK because 33.3% is 0.333, which is between 0 and 1

B) NOT OK, because probability isn't negative

C) 0.0002 is in between 0 and 1, so possible

D) 0 probability means it can't happen, so that's okay as well

E) this is a fraction with numerator less than denominator, which means its between 0 and 1, so OK

F) this fraction's numerator is greater than denominator, so it's greater than 1. Probability can't be greater than 1, so NOT OK

Out of these B and F cannot represent the probability of an event

6 0
3 years ago
The area of a parallelogram is 16.8 square inches. If the base of the parallelogram is 1.5 inches, what is its height?
zubka84 [21]

Answer: the height is 11.2

Step-by-step explanation:

5 0
3 years ago
Point a pq and r are collinear on pr and pq: pr =2/3. P is located on the origin q is located at (x,y) and r is located at (-12,
dybincka [34]

The values of x and y are  8 and 0 respectively.

<em><u>Explanation</u></em>

As 'p' is located at (0,0) and 'r'  is located at (-12,0) , that means both 'p' and 'r' are on the x-axis.  So point 'q' will be also on the x-axis , and 'q' is located at (x,y)

So, the value of y will be 0. That means the co ordinate of point 'q' is (x, 0)

Now, using the Distance formula, length of 'pq' = \sqrt{(x-0)^2 +(0-0)^2}= \sqrt{x^2}= x

and length of  'pr'  = \sqrt{(-12-0)^2+(0-0)^2}= \sqrt{144}=12

Given that,   pq : pr =2/3

So....

\frac{x}{12} =\frac{2}{3}\\ \\ 3x=24\\ \\ x= \frac{24}{3}=8

Thus, the values of x and y are  8 and 0 respectively.

8 0
4 years ago
Please help me with this -.-
Shtirlitz [24]

Answer:

m=4

Step-by-step explanation:

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8 0
3 years ago
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Complete the equation describing how x and y are related.
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-5 would be the blank.
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