1300 = 1000 (1.08)^t
1.3 = (1.08)^t
log base 1.08 (1.3) = t
3.41 = t
Answer:
1. 5IN = 9 OUT
2. -3 IN= -7 OUT
3. 4 IN = 7 OUT
4. -9 IN = -20 OUT
Step-by-step explanation:
Answer:
5,000.....................................
Answer:
-4x^3 +12x^2 for 0 < x < 3
Step-by-step explanation:
The power rule is appropriate:
(d/dx)x^n = n·x^(n-1)
This is applied to each of the terms.
F'(x) = -(4·x^3) +4(3x^2) +0
F'(x) = -4x^3 +12x^2 . . . . for 0 < x < 3
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The derivative is not defined at the endpoints of the interval, so F'(x) is only defined on (0, 3), not [0, 3].
P(-1, 1)
G(2,1)
R(1,-3)
S(-2,-3)
