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zmey [24]
3 years ago
12

Please help!!:

Mathematics
1 answer:
LenKa [72]3 years ago
5 0

Answer:

B

Step-by-step explanation:

I just took test

please make me Brainliest

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Given an initial quantity Q0=150 and a growth rate of 7% per unit time, give a formula for the quantity Q as a function of time
rodikova [14]

Answer:

Step-by-step explanation:

From the given information:

(a)

Since growth quantity is not continuous

Q(t) = 150 (1.07)^t

For t = 10

Q(10) = 150 (1.07)^{10}

\mathbf{Q(10) = 295.073}

(b)

Here, for a continuous growth rate, the growth quantity can be computed in terms of initial quantity and the growth rate.

i.e.

Q(t) = 150 e^{0.07t}

At t = 10 for a continuous growth rate;

Q(10) = 150 e^{0.07  \times 10}

Q(10) = 150 e^{0.7}

\mathbf{Q(10) = 302.063}

8 0
3 years ago
Find the area of ΔABC. vertices are A(2, 1), B(3, 3), and C(1, 6)
Karolina [17]

Answer:

area = (1/2)|Ax(By-Cy) +Bx(Cy-Ay) +Cx(Ay-By)|

 = (1/2)|2(3-6) +3(6-1) +1(1-3)| = (1/2)|-6 +15 -2|

 area = 7/2

learn at brainly.com/question/17119045

7 0
3 years ago
4x = 40 a) X =10 b) X = 36 c) X = 44 D) x = 160
goldfiish [28.3K]

Answer: ax=10 cause u multiply 4x10=40=40

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Solve for x. 4−(2x+4)=5 x=6 x=−52 x=−10 x=32
sashaice [31]

Answer:

Step-by-step explanation:

4−(2x+4)=5

4-2x - 4 =5

-2x = 5

x= -5/2 = -2.5

5 0
3 years ago
HELP ME PLEASE!!!!!
son4ous [18]

Answer:

I think the answer (-2, 6)

8 0
3 years ago
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