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SVEN [57.7K]
4 years ago
14

If £2000 is placed into a bank account that pays 3% compound interest per year, how much will be in the account after 2years?

Mathematics
2 answers:
AVprozaik [17]4 years ago
5 0
3% = 3/100 = 0,03

When it's compount interest it's 1,03 because you gain 3% more from what you already have.

All you need to do
1,03•2000=2060$ for the first year

And then for the second year, you take the actual amount after one year of 3%

1,03•2060=2121,8

After two years, there will be 2121,8$
GrogVix [38]4 years ago
5 0

Answer:

Hey!

Your answer is £2121.80 in the account!

Step-by-step explanation:

So to do this, you have to first find out how much would be left after 1 year...

=     3 / 100 x 2000 = £60 *we now add this on to the £2000*

=     2000 + 60 = £2060 *this is what is in the account after 1 YEAR*

Then, find out the amount for the second year!

=     3 / 100 x 2060 = £61.80 *we now add this on to the £2060*

=     2060 + 61.80 = £2121.80 *this is what is in the account after 2 YEARS*

SO AFTER 2 YEARS, THERE IS AN AMOUNT OF £2121.80 IN THE BANK ACCOUNT!

HOPE THIS HELPS!!

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If you invested $600 at 3% simple interest for 2 years, how much interest do you earn? Show work and answer in complete sentence
zzz [600]

Answer:

I would rather do the second option of which uses Compound interest that will give a profit of $47.85

Step-by-step explanation:

In this problem we will be exploring the two formulas

1. simple interest

A= P(1+r*t)

2. compound interest

A= P(1+r/n)^nt

Where A= final amount

P= initial amount

r= rate

t= time.

n= number of periods Compounded

1.given data

P= $600

r= 3%= 3/100= 0.03

t= 2 years

A= 600(1+0.03*2)

A= 600(1+0.06)

A= 600(1.06)

A= $636

Interest = 636-600= $36

2. Given data

P= $600

r= 4%= 4/100= 0.04

n= 24

t= 2

A= 600(1+0.04/24)^24*2

A=600(1+0.0016)^48

A=600(1.0016)^48

A= 600*1.07975

A= 647.85

Interest = 647.85-600= $47.85

7 0
3 years ago
Consider a pattern that begins with 9 and each consecutive number is twice the previous term. What are the first four terms of t
ahrayia [7]

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