3 years ago

I meed help asap i really do t get this

Mathematics

2 answers:

PtichkaEL [24]3 years ago

8 0

Answer:

A. |-80| < 80

Step-by-step explanation:

Olenka [21]3 years ago

3 0

It’s b that the answer to the question

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Please help, I'll mark brainliest.

GREYUIT [131]

I'm almost certain it's C :)

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3 years ago

What is the ratio of our solar system's radius to the Milky Way's radius given that the distance from Pluto to the sun is 5.9 *

kherson [118]

Answer:

Just divide the sun-pluto distance by the milky way radius and you get the following ratio:

6.6 x 10^7 : 1

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3 years ago

Circles M and K are congruent and QR is congruent to LN. Find QR

ddd [48]

At first, we need to find x.

QR = LN

2x+1 = 3x-7

x=8

Substitute value of a=8 into QR = 2x+1.

QR = 2*8+1 = 17

QR =17

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3 years ago

PQRS has vertices P(0, 0), Q(4, 2), and S(4, ␣2). Its diagonals intersect at H(4, 0). What are the possible coordinates of R for

True [87]

Any point on the x-axis beyond the point (4, 0) is a possible cordinate of R.

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3 years ago

In a geometric sequence, a4 = 54 and a7 = 1,458. what is the 12th term? <br><br> answer: B) 354,294

slamgirl [31]

Option B:

The 12th term is 354294.

Solution:

Given data:

$a_4=54$ and $a_7=1458$

To find $a_{12}:$

The given sequence is a geometric sequence.

The general term of the geometric sequence is $a_n=a_1\ r^{n-1}$ .

If we have 2 terms of a geometric sequence $a_n$ and $a_k$ (n > K),

then we can write the general term as $a_n=a_k\ r^{n-k}$ .

Here we have $a_4=54$ and $a_7=1458$ .

So, n = 7 and k = 4 ( 7 > 4)

$a_7=a_4\ .\ r^{7-4}$

$1458=54\ . \ r^3$

This can be written as

$$r^3=\frac{1458}{54}$

$$r^3=27$

$$r^3=3^3$

Taking cube root on both sides of the equation, we get

r = 3

$a_{12}=a_7\ .\ r^{12-7}$

$=1458\ .\ r^5$

$=1458\ .\ 3^5$

$a_{12}=354294$

Hence the 12th term of the geometric sequence is 354294.

7 0

3 years ago