Answer:
12πx⁴, 15x⁷, 16x⁹
Step-by-step explanation:
Volume of a cylinder: πr²h
Volume of a rectangular prism: whl
Plugging in variables for the volume of a cylinder, we get: 3x²·(2x)²·π
3x²·(2x)² = 3·2·2·x·x·x·x
= 12·x⁴
=12x⁴
Now, we just multiply that by π.
12x⁴·π = 12x⁴π
A monomial is a 1-term polynomial, so 12x⁴π is a monomial.
Plugging in variables for the volume of a rectangular prism, we get: 5x³·3x²·x²
5x³·3x² = 5·3·x·x·x·x·x
= 15·x⁵
= 15x⁵
Now, we just multiply that by x².
15x⁵·x²
= 15·x·x·x·x·x·x·x
= 15·x⁷
=15x⁷
A monomial is a 1-term polynomial, so 15x⁷ is a monomial.
Same steps for the last shape, another rectangular prism:
2x²·2x³·4x⁴
2x²·2x³
= 2·2·x·x·x·x·x
= 4·x⁵
= 4x⁵
Now, we just multiply that by 4x⁴.
4x⁵·4x⁴
= 4·4·x·x·x·x·x·x·x·x·x·
= 16·x⁹
= 16x⁹
A monomial is a 1-term polynomial, so 16x⁹ is a monomial.
Answer:
9 units right and 7 units up! You can check!!! D!
Step-by-step explanation:
Brainliest???
Here's how to convert 0.16666 to a fraction...
There is not much that can be done to figure out how to write 0.16666 as a fraction, except to literally use what the decimal portion of your number, the .16666, means.
Since there are 5 digits in 16666, the very last digit is the "100000th" decimal place.
So we can just say that .16666 is the same as 16666/100000.
The fraction 16666/100000 is not reduced to lowest terms. We can reduce this fraction to lowest
terms by dividing both the numerator and denominator by 2.
Why divide by 2? 2 is the Greatest Common Divisor (GCD)
or Greatest Common Factor (GCF) of the numbers 16666 and 100000.
So, this fraction reduced to lowest terms is 8333/50000
So your final answer is: 0.16666 can be written as the fraction 8333/50000
X=his fortune
15/16X=7500
X=7500 x 16/15
X=8000
Answer:
Part A: 60
5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60.
12, 24, 36, 48, 60.
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Part B: 9
81 / 72 = 9
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Part C: 9 (8 + 9)
GCF of 72 and 81 is 9...
Divide 72 by 9 and get 8.
Divide 81 by 9 and get 9.
To check multiply 9 with 8, and multiply 9 by 9.
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Easy! :D (if you don't mind, may I get brainliest please?)