Answer:
the answer is -9 it think
Answer:
JL = 70
Step-by-step explanation:
Since K is the midpoint of JL then JK = KL and
JL = JK + KL = 9x - 1 + 2x + 27 = 11x + 26
solve for x using JK = KL
9x - 1 = 2x + 27 ( subtract 2x from both sides )
7x - 1 = 27 ( add 1 to both sides )
7x = 28 ( divide both sides by 7 )
x = 4, hence
JL = 11x + 26 = (11 × 4 ) + 26 = 44 + 26 = 70
<span>Use a straightedge to join points W and P and then points P and X. â–łWPX is equilateral.
Let's see now, Delmar has a line segment WX and has drawn 2 circles whose radius is the length of WX, centered upon W and centered upon X. Sounds to me that all he needs to do is select one of the intersections of those 2 circles and use that at the 3rd point of the equilateral triangle and draw a line from that point to W and another line from that point to X. Doesn't matter which of the two intersections he chooses, just needs to pick one. Looking at the available options, only the 1st one which is "Use a straightedge to join points W and P and then points P and X. â–łWPX is equilateral." matches my description, so that is the correct choice. The other choices tend to do rather bizarre things like create a perpendicular bisector of WX and for some unknown reason, claim that bisector is somehow a side of a desired equilateral triangle.</span>
(8)=ones place
(1)0=tens place
(1)00=hundreds place
(9)000=thousands place
The "1" beside the 8, is the tenths spot so you would round that part of the number.
Therefore the answer would be:
9120