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babunello [35]
3 years ago
6

7. There are 15 printers in one department. If 2/5 are color printers, how many can only print black and

Mathematics
2 answers:
scZoUnD [109]3 years ago
6 0

Answer:

9

Step-by-step explanation:

Multiply 2/5 by three, creating 6/15. subtract 15 by 6, 15-6=9

Lina20 [59]3 years ago
5 0
The correct answer is B. 9
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Arrange these plants by height from shortest to tallest: 3.6m, .45m, 6.2m, 1.23m
jarptica [38.1K]

Answer:

0.45m , 1.23 m, 3.6m, 6.2m

Step-by-step explanation:

Remember to note the placement of the decimal points. The greater the number(s) leaning towards the left, the greater the number will be.

~<em>Senpai</em>

8 0
4 years ago
How to write an area formula using the sides of the triangle a,b,c?
bearhunter [10]

Answer:

A=hb b/2

Step-by-step explanation:

area=height(sub)base times base divided by 2


4 0
3 years ago
Consider the age distribution in the United States in the year 2075 (as projected by the Census Bureau). Construct a cumulative
MrRissso [65]

Answer:

The cumulative frequency plot is also attached below.

Step-by-step explanation:

The data provided is as follows:

Age Group Frequency

   0 - 9             34.9

  10 - 19             35.7

20 - 29             36.8

30 - 39             38.1

40 - 49             37.8

50 - 59             37.8

60 - 69             34.5

70 - 79             27.2

80 - 89             18.8

90 - 99               7.7

100 - 109       1.7

Consider the Excel output attached.

The cumulative frequency are computed in the Excel sheet.

The cumulative frequency plot is also attached below.

From the cumulative frequency plot it can be seen that in the future most people will belong to a higher age group rather then the lower ones.

8 0
3 years ago
What's the answer to this??
Evgen [1.6K]
The variable "x" equals 7
3 0
3 years ago
50+51+52+...+101=...<br>Can you help me? I do not understand
Dmitriy789 [7]

Suppose

S=50+51+52+\cdots+100+101

At the same time, we can write

S^*=101+100+99+\cdots+51+50

Note that S=S^* (just reverse the sum). Let's pair the first terms of S and S^*, and the second, and the third, and so on:

S+S^*=(50+101)+(51+100)+(52+99)+\cdots+(100+51)+(101+50)

Now, each grouped term in the sum on the right side adds to 151. There are 52 grouped terms on that same side (because there are 50 numbers in the range of integers 51-100, plus 50 and 101), which menas

S+S^*=52\cdot151

But S=S^*, as we pointed out, so

2S=52\cdot151\implies S=\dfrac{52\cdot151}2=3926

5 0
3 years ago
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