Answer:
z²^30
Step-by-step explanation:
This is it enjoy.
100 times (6+5)
100 times 11
100 groups of 11=1100
Hope I helped:)
Subsitution
solve for y in first equation
add 2x to both sides
y=2x+8
sub 2x+8 for y in second equation
16+4x=2(2x+8)
divide both sides by 2
8+2x=2x+8
true
there are infinite solutions for x
therefor infinite soltions for y
there are an infinite number of solutions
Answer:
A and C
Step-by-step explanation:
