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Alexeev081 [22]
3 years ago
8

Is it possoble for a system of linear equations to have no solution​

Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
8 0

Yes This Is Possible. This Would Happen If The Lines Never Intersected With Each Other. If This Was The Case, There Would Be No Point That Lies On Both Lines. Have A Great Day!

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How can I solve the statement below?
QveST [7]

9514 1404 393

Answer:

  A ≈ 65.4°

Step-by-step explanation:

The mnemonic SOH CAH TOA is intended to remind you of the trig relations associated with pairs of sides. For angle A, given sides b and c are the adjacent side and the hypotenuse, respectively. The appropriate relation is ...

  Cos = Adjacent/Hypotenuse

  cos(A) = b/c

  A = arccos(b/c) = arccos(2.5/6)

  A ≈ 65.4°

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3 years ago
EXTRA POINTS * how do you graph y=2x + 1
ahrayia [7]

Step-by-step explanation:

first u need to pick a random coordinate to substitute the X . example 0

y = 2(0) + 1

y =1 , X= 0

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then you continue this same process and again until u have at least two points to draw a straight line. it kinda depended if u want to fill the entire graph.

3 0
3 years ago
X= 0 , 1 , or 7<br> Y= -10, 5, or 10<br> Please helppppp will mark Brainliest
vlabodo [156]

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Best known for its testing program, ACT, Inc., also compiles data on a variety of issues in education. In 2004 the company repor
GarryVolchara [31]

Answer:

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

Step-by-step explanation:

Check for conditions

For this case in order to use the normal distribution for this case or the 68-95-99.7% rule we need to satisfy 3 conditions:

a) Independence : we assume that the random sample of 400 students each student is independent from the other.

b) 10% condition: We assume that the sample size on this case 400 is less than 10% of the real population size.

c) np= 400*0.74= 296>10

n(1-p) = 400*(1-0.74)=104>10

So then we have all the conditions satisfied.

Solution to the problem

For this case we know that the distribution for the population proportion is given by:

p \sim N(p, \sqrt{\frac{p(1-p)}{n}})

So then:

\mu_p = 0.74

\sigma_p =\sqrt{\frac{0.74(1-0.74)}{400}}=0.0219

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

5 0
3 years ago
Evaluate the expression for the given values of the variables.
vfiekz [6]

Answer:

A

Step-by-step explanation:

Substitute the given values into the expression

2a² + cb

= 2(5)² + 3(11)

= 2(25) + 33

= 50 + 33

= 83 → A

7 0
2 years ago
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