Answer:
112
Step-by-step explanation:
Just solve it easy peasy
![7[(25+9)-3(2-1)]](https://tex.z-dn.net/?f=7%5B%2825%2B9%29-3%282-1%29%5D)
First solve the inner brackets
![7[(34)-3(3)]\\7[25-9]](https://tex.z-dn.net/?f=7%5B%2834%29-3%283%29%5D%5C%5C7%5B25-9%5D)
Now the other brackets
![7[25-9]\\7[16]\\112](https://tex.z-dn.net/?f=7%5B25-9%5D%5C%5C7%5B16%5D%5C%5C112)
Answer:
D
Step-by-step explanation:
I've done it before
so its d
good luck
hope you get a good grade
Regardless of the size of the square, half the diagonal is (√2)/2 times the side of the square.
The ratio is (√2)/2.
_____
Consider a square of side length 1. The Pythagorean theorem tells you the diagonal measure (d) is ...
... d² = 1² +1² = 2
... d = √2
The distance from the center of the square to one of its corners (on the circumscribing circle) is then d/2 = (√2)/2. This is the radius of the circle in which our unit square is inscribed.
Since we're only interested in the ratio of the radius to the side length, using a side length of 1 gets us to that ratio directly.
Answer:
True
Step-by-step explanation:
plz mark brainliest