Answer:
<em>The SUV is running at 70 km/h</em>
Step-by-step explanation:
<u>Speed As Rate Of Change
</u>
The speed can be understood as the rate of change of the distance in time. When the distance increases with time, the speed is positive and vice-versa. The instantaneous rate of change of the distance allows us to find the speed as a function of time.
This is the situation. A police car is 0.6 Km above the intersection and is approaching it at 60 km/h. Since the distance is decreasing, this speed is negative. On the other side, the SUV is 0.8 km east of intersection running from the police. The distance is increasing, so the speed should be positive. The distance traveled by the police car (y) and the distance traveled by the SUV (x) form a right triangle whose hypotenuse is the distance between them (d). We have:

To find the instant speeds, we need to compute the derivative of d respect to the time (t). Since d,x, and y depend on time, we apply the chain rule as follows:

Where x' is the speed of the SUV and y' is the speed of the police car (y'=-60 km/h)
We'll compute :


We know d'=20 km/h, so we can solve for x' and find the speed of the SUV

Thus we have

Solving for x'

Since y'=-60


The SUV is running at 70 km/h
Answer:
The answer is 3
Step-by-step explanation:
Answer:
AA Similarity Postulate
Step-by-step explanation:
we know that
If two figures are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent
step 1
Verify the proportion of the corresponding sides

substitute

----> is true
Corresponding sides are proportional
Triangle PQR is similar to Triangle PST
That means
Corresponding angles must be congruent
side QR is parallel side ST
and
----> by corresponding angles
--> by corresponding angles
so
PQR is similar to PST by AA Similarity Postulate
Answer:
y = 96°
Step-by-step explanation:
The measure of the inscribed angle y is half the measure of its intercepted arc.
The whole circle = 360°
the intercepted arc = 360° - 168° = 192°
Thus
y =
× 192° = 96°