Answer:
answer for this question is 6
a) situation you’re familiar with where one quantity changes constantly in relation to another quantity is Velocity = Distance/Time
b) the velocity is in direct proportion to distance and inverse relation to time.
c) The graph shown by velocity- time is a straight line graph.
<h3>what is algebra?</h3>
Algebra is a branch of mathematics that deals with symbols or variables and uses arithmetic operations (+, –, ×, ÷) to find the unknown quantities represented by these variables.
There is a equation we are familiar with , the equation of motion
Velocity = Distance/Time
Here, velocity increases or decreases if the distance also increases or decreases. But if time increases velocity decreases.
So, the velocity is in direct proportion to distance and inverse relation to time.
The graph shown by velocity- time is a straight line graph.
Learn more about algebra here:
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Answer:
y=4−2x/3
Step-by-step explanation:
Move all terms that don't contain y to the right side and solve.
Answer:
the ball reaches a height of 64 feet after 2 sec.
The ball is in the air 4 sec.
Step-by-step explanation:
The ball is following the path of a parabola. The maximum height is at the vertex of the parabola.
Let (h, k) be the vertex. h will be the time it takes to reach the maximum height, and k will be that height.
y = 
h = -b/2a = 64/(-2)(-16) = 64/32 = 2
k = -16(2)^2 + 64(2)
-16(4) + 128
- 64 + 128 = 64
V: (2, 64)
So the ball reaches a height of 64 feet after 2 sec.
Let = 0 (0 is the height when the balls hits the ground)
-16t(t - 4) = 0
t = 0 or t = 4
The ball is in the air 4 sec.
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